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irina [24]
3 years ago
6

Two students are discussing the use of a trial balance. They wonder whether the following errors, each considered separately, wo

uld prevent the trial balance from balancing. (a) The bookkeeper debited Cash for $600 and credited Salaries and Wages Expense for $600 for payment of wages. (b) Cash collected on account was debited to Cash for $900 and Service Revenue was credited for $90. What would you tell them
Business
1 answer:
Natali [406]3 years ago
7 0

Answer:

The use of a trial balance:

a) This error will not cause the two sides of the trial balance to disagree. A compensating error has occurred, because the Cash Account should have been credited and the Salaries and Wages Expense debited with $600.

b) This error will cause the two sides of the trial balance to disagree.  The amount debited is not the same amount credited.  The Accounts Receivable should have been credited with $900, not the Service Revenue.

Explanation:

a) The trial balance ensures that the total values of the debit and credit sides agree.  It shows that accounts have been correctly debited and credited in the general ledger, with equal amounts.

b) Compensating errors arise when two accounting errors offset themselves, because the same mistake made on the debit side is made on the credit side

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Smith has applied overhead of $73,000 and actual overhead of $87,600 for the month of November. It applies overhead based on dir
oee [108]

Answer:

Estimated direct labor hours= 180,000

Explanation:

Giving the following information:

Overhead for the year was estimated to be $900,000.

Smith has applied overhead of $73,000

It applies overhead based on direct labor hours and those equaled 14,600 in November.

We have to reverse engineer the allocation method for manufacturing overhead.

First, we need to calculate the estimated overhead rate:

Allocated MOH= Estimated manufacturing overhead rate* Actual amount of allocation base

73,000= Estimated manufacturing overhead rate*14,600

$5= Estimated manufacturing overhead rate

Estimated manufacturing overhead rate= $5 per direct labor hour

Now, we can determine the estimated direct labor hours:

Estimated manufacturing overhead rate= total estimated overhead costs for the period/ total amount of allocation base

5= 900,000/ total amount of allocation base

5*X= 900,000

total amount of allocation base= 180,000

Estimated direct labor hours= 180,000

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3 years ago
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Tamarisk, Inc. sells merchandise on account for $2500 to Culver Company with credit terms of 2/15, n/30. Culver Company returns
denis23 [38]

Answer:

$2,254

Explanation:

The computation of the amount of the check is shown below:

= Sale value of merchandise - returned goods - discount amount

where,

Sale value of merchandise is $2,500

Returned goods is $200

And, the discount is 2% of $2,300 = $46

So, the amount of the check is

= $2,500 - $200 - $46

= $2,254

We simply applied the above formula so that the correct amount could come

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3 years ago
Estimate the liquid density (g/cm3) of propane at 298 K and 10 bar. Compare the price per kilogram of propane to the price of re
Deffense [45]

Answer:

Density of propane = 17.8 g/L

Propane is more priced than gasoline

Explanation:

Given:

Temperature, T = 298 K

Pressure, P = 10 bar = 0.987 × 10 = 9.87 atm

now,

Molar mass of propane, M = 44.1 g/mol

From ideal gas law

⇒ PV = nRT

here,

n is the number of moles

R is the ideal gas constant = 0.0821 L.atm/mol.K

also,

Density, D = \frac{\textup{Mass}}{\textup{Volume(V)}}

or

V = \frac{\textup{Mass}}{\textup{D}}

and,

nM = mass

thus,

V = \frac{\textup{nM}}{\textup{D}}

substituting in the ideal gas relation

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P = \frac{\textup{DRT}}{\textup{M}}

or

D = \frac{\textup{PM}}{\textup{RT}}

or

D = \frac{9.87\times44.1}{0.0821\times298}

or

D = 17.8 g/L

Now,

1 gallon = 3.78 Liter

Therefore,

5 gallon = 5 × 3.78 Liter = 18.9 Liter

Thus,

mass of 5 gallon propane = Volume × Density

= 18.9 Liter × 17.8 g/L

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or

= 0.336 kg

also it is given that Price of 5 gallon propane i.e 0.336 kg = $30

Therefore,

Price per kg = \frac{30}{0.336}

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and,

Mass of 5 gallons i.e 18.9 Liter gasoline = Density × Volume

= 0.692 g/cm³ × 18.9 Liter

also,

1 L = 1000 cm³

thus,

= 0.692 g/cm³ × 18.9 × 1000 cm³

= 13078.8 g

or

= 13.078 kg

Therefore,

Price per kg of gasoline = \frac{\$30}{13.078}

= $2.29

hence, propane is more priced than gasoline

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