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3 years ago

Please help! 20 points!

Mathematics

1 answer:

aleksandr82 [10.1K]3 years ago

7 0

This seems hard lol ill be back with an answer g

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kherson [118]

Hey, Can i get the table?

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3 years ago

48x^2 +44x=60 which of the following could be used to find the solution to the equation above? Select all that apply

levacccp [35]

Because the polynomial has degree 2, we can assume that there are 2 solutions (roots), whether real or imaginary.

You can subtract 60 in order to put this in standard form

48x^2+44x-60 = 0

From there, just put a,b, and c into the quadratic formula and you're good to solve for your answers.

(-b+-sqrt(b^2-4ac))/2a

(-44+-sqrt(44^2-4(48)(-60)))/2(48)

Then solve.

There is probably a better way, but this should give you the two roots/solutions.

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3 years ago

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Step-by-step explanation:

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2 years ago

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Step-by-step explanation:

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2 years ago

1360 concert tickets were sold for a total of $13,328. If students paid $8 and non students paid $12, how many student tickets w

lyudmila [28]

748 student tickets were sold.

Step-by-step explanation:

Given,

Number of tickets sold = 1360

Revenue generated = $13328

Cost of each student ticket = $8

Cost of each non student ticket = $12

Let,

x be the number of student tickets sold

y be the number of non student tickets sold

According to given statement;

x+y=1360 Eqn 1

8x+12y=13328 Eqn 2

Multiplying Eqn 1 by 12

$12(x+y=1360)\\12x+12y=16320\ \ \ Eqn\ 3$

Subtracting Eqn 2 from Eqn 3

$(12x+12y)-(8x+12y)=16320-13328\\12x+12y-8x-12y=2992\\4x=2992\\$

Dividing both sides by 4

$\frac{4x}{4}=\frac{2992}{4}\\x=748$

748 student tickets were sold.

Keywords: linear equation, elimination method

Learn more about elimination method at:

#LearnwithBrainly

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2 years ago