Hey, Can i get the table?
Because the polynomial has degree 2, we can assume that there are 2 solutions (roots), whether real or imaginary.
You can subtract 60 in order to put this in standard form
48x^2+44x-60 = 0
From there, just put a,b, and c into the quadratic formula and you're good to solve for your answers.
(-b+-sqrt(b^2-4ac))/2a
(-44+-sqrt(44^2-4(48)(-60)))/2(48)
Then solve.
There is probably a better way, but this should give you the two roots/solutions.
Answer:
forstone
Step-by-step explanation:
sike I lied I dont know this RESPECTFULYY!!
Answer:
b
Step-by-step explanation:
748 student tickets were sold.
Step-by-step explanation:
Given,
Number of tickets sold = 1360
Revenue generated = $13328
Cost of each student ticket = $8
Cost of each non student ticket = $12
Let,
x be the number of student tickets sold
y be the number of non student tickets sold
According to given statement;
x+y=1360 Eqn 1
8x+12y=13328 Eqn 2
Multiplying Eqn 1 by 12

Subtracting Eqn 2 from Eqn 3

Dividing both sides by 4

748 student tickets were sold.
Keywords: linear equation, elimination method
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