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seraphim [82]
3 years ago
13

Help will give crown

Mathematics
1 answer:
AleksandrR [38]3 years ago
5 0

Answer:

112 meters squared

Step-by-step explanation:

Rectangle area: 72

Triangle area: 20 times 2 (because there are two triangles) = 40

72 + 40 = 112

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Y=–6x+2
Verizon [17]

Answer:

3 no solution

Step-by-step explanation:

I'm a smart man I would know trust me

I have my masters degree

7 0
3 years ago
Keegan is printing and selling his original design on t-shirts. He has concluded that for x shirts, in thousands sold his total
Katarina [22]

Answer:

t-shirts: 2790

profit: $12209

Step-by-step explanation:

Given  the function:

p(x) = -x³ + 4x² + x

we want to maximize it.

The following criteria must be satisfied at the maximum:

dp/dx = 0

d²p/dx² < 0

dp/dx = -3x² + 8x + 1 = 0

Using quadratic formula:

x = \frac{-b \pm \sqrt{b^2 -4(a)(c)}}{2(a)}

x = \frac{-8 \pm \sqrt{8^2 -4(-3)(1)}}{2(-3)}

x = \frac{-8 \pm 8.72}{-6}

x_1 = \frac{-8 + 8.72}{-6}

x_1 = -0.12

x_2 = \frac{-8 - 8.72}{-6}

x_2 = 2.79

d²p/dx² = -6x + 8

d²p/dx² at x = -0.12: -6(-0.12) + 8 = 8.72 > 0

d²p/dx² at x = 2.79: -6(2.79) + 8 = -8.74 < 0

Then, he should prints 2.79 thousands, that is, 2790 t-shirts to make maximum profits.

Replacing into profit equation:

p(x) = -(2.79)³ + 4(2.79)² + 2.79 =  12.209

that is, $12209

3 0
3 years ago
If r(x) = 2 – x2 and w(x) = x – 2, what is the range of w(r(x))
Paladinen [302]
Range is the outputs possible
w(r(x))=(2-x^2)-2
w(r(x))=2-x^2-2
w(r(x))=-x^2

therefor the range is from 0 to -∞
5 0
3 years ago
Read 2 more answers
Find the midpoint of the segment with the following end points (10,5) and (6,9)
Taya2010 [7]

Answer:

The mid-point between the endpoints (10,5) and (6,9) is:

  • \left(x,\:y\right)=\left(8,\:7\right)

Step-by-step explanation:

Let (x, y) be the mid-point

Given the points

  • (10,5)
  • (6,9)

Using the formula to find the mid-point between the endpoints (10,5) and (6,9)

\left(x,\:y\right)=\left(\frac{x_2+x_1}{2},\:\:\frac{y_2+y_1}{2}\right)

Here:

\left(x_1,\:y_1\right)=\left(10,\:5\right),\:\left(x_2,\:y_2\right)=\left(6,\:9\right)

Thus,

\left(x,\:y\right)=\left(\frac{x_2+x_1}{2},\:\:\frac{y_2+y_1}{2}\right)

\left(x,\:y\right)=\left(\frac{6+10}{2},\:\frac{9+5}{2}\right)

\left(x,\:y\right)=\left(8,\:7\right)

Therefore, the mid-point between the endpoints (10,5) and (6,9) is:

  • \left(x,\:y\right)=\left(8,\:7\right)
3 0
3 years ago
-4z ≥ - 64.4
nignag [31]

Answer: D

Step-by-step explanation:

5 0
2 years ago
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