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algol [13]
2 years ago
13

Find the Error. Judith states that -|14| = 14 because the absolute value can never be negative. Find her mistake and correct it.

Mathematics
1 answer:
AURORKA [14]2 years ago
5 0

Answer:

-14

Step-by-step explanation:

The negative sign is not inside of the absolute value sign so it would be -14

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ZA and ZB are supplementary angles. If mZA = (5x + 25)° and m
liberstina [14]

Answer:

MZA = 140

Step-by-step explanation:

5x+25°+ x + 17°=180°(Supplimentary Angles)

6x + 42° =180°

6x =180 - 42

6x=138

(divide by 6 both sides)

X= 23

substitution X into the given angle

5x +25

5(23)+25

115+25

140

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2 years ago
Who does e.d.e.n.u.i.t.y and needs help catching up?/ I'm free to help... only up to 8th grade though...
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Answer:

we might be starting it again soon

Step-by-step explanation:

Im in 7th and I might need help!!

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2 years ago
Assume the amount you can spend on car payments is 50% of your monthly surplus.
nikdorinn [45]
773.77*0.5=386.88 hope i helped
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3 years ago
Would you classify the number 289 as a perfect​ square, perfect​ cube, both, or​ neither?
Black_prince [1.1K]

Answer:

a perfect square because 17 x 17 = 289

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Step-by-step explanation:

7 0
3 years ago
HELP WITH THESE QUESTIONS PART 2.
polet [3.4K]

Answer: (a) IV (b) positive (c) \frac{\pi}{4} (d) C (e) \sqrt{2}

<u>Step-by-step explanation:</u>

a) \frac{15\pi}{4} - \frac{8\pi}{4} = \frac{7\pi}{4}, which is located in Quadrant IV <em>per the Unit Circle.  </em>

b) sec is \frac{1}{cos}. Cos is the x-coordinate.  The x-coordinate inQuadrant IV is positive.

c) the reference angle is the angle from \frac{7\pi}{4} to 2π = \frac{\pi}{4}

d) since the angle is below the x-axis and the reference angle is\frac{\pi}{4}, then the angle is equal to -sec(\frac{\pi}{4})

e) sec = \frac{1}{cos}   ⇒   sec \frac{7\pi}{4} = \frac{2}{\sqrt{2} } = \frac{2}{\sqrt{2} }(\frac{\sqrt{2}} {\sqrt{2}}) = \frac{2\sqrt{2} }{2} = \sqrt{2}

**********************************************************

Answer: (a) \frac{3\pi}{2} (b) (0, -1) (c) A (d) -1

<u>Step-by-step explanation:</u>

a) \frac{11\pi}{2} - \frac{4\pi}{2} = \frac{7\pi}{2} - \frac{11\pi}{2} = \frac{3\pi}{2}

b) \frac{3\pi}{2} is on the Unit Circle at (0, -1)

c) sin = \frac{opposite}{hypotenuse} which equals \frac{y}{r} on the Unit Circle.

d) sin is the y-coordinate. sin (\frac{3\pi}{2}) = -1

6 0
3 years ago
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