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kati45 [8]
3 years ago
6

Question in picture solve

Mathematics
1 answer:
balandron [24]3 years ago
3 0

Answer:

x int (-3,0) and x int (2,0)

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What are greater than and less than symbols?
schepotkina [342]
> is greater than
< is less than
4 0
4 years ago
The sum of two consecutive integers is 131. What are the integers?
Dahasolnce [82]
X, x+1
x+x+1=131
2x+1=131
2x=131-1=130
x=130÷2 = 65
the integers are 65 and 66
3 0
3 years ago
If side b measures 5√3, what is the length of side c?
Leviafan [203]

Answer:

10

Step-by-step explanation:

cos(30) = b / c

c = b / cos(30)

c = 5xsqrt(3) / 0.866

c = 10

6 0
2 years ago
Can someone please answer these questions to help me understand? Please and thank you! Will mark as brainliest!!
Nadya [2.5K]

QUESTION 1  

If a function is continuous at x=a, then \lim_{x \to a}f(x)=f(a)  

Let us find the limit first,  

\lim_{x \to 4} \frac{x-4}{x+5}  

As x \rightarrow 4, x-4 \rightarrow 0,x+5 \rightarrow 9 and f(x) \rightarrow \frac{0}{9}=0  

\therefore \lim_{x \to 4} \frac{x-4}{x+5}=0  

Let us now find the functional value at x=4  

f(4)=\frac{4-4}{4+5} =\frac{0}{9}=0  

Since  

\lim_{x \to 4} f(x)=\frac{x-4}{x+5}=f(4), the function is continuous at a=4.  

QUESTION 2  

The correct answer is table 2. See attachment.


In this table the values of x approaches zero from both sides.


This can help us determine if the one sided limits are approaching the same value.

As we are getting closer and closer to zero from both sides, the function is approaching 2.


The values are also very close to zero unlike those in table 4.


The correct answer is B


QUESTION 3


We want to evaluate;


\lim_{x \to 1} \frac{x^3+5x^2+3x-9}{x-1}


using the properties of limits.


A direct evaluation gives \frac{1^3+5(1)^2+3(1)-9}{1-1}=\frac{0}{0}.


This indeterminate form suggests that, we simplify the function first.


We factor to obtain,


\lim_{x \to 1} \frac{(x-1)(x+3)^2}{x-1}


We cancel common factors to get,


\lim_{x \to 1} (x+3)^2


=(1+3)^2=16


The correct answer is D



QUESTION 4

We can see from the table that as x approaches -2 from both sides, the function approaches -4


Hence the limit is -4.


See attachment


The correct answer is option A

3 0
3 years ago
Giovanni and Jean started a 120-mile bicycle race at the same time. Giovanni cycled at 23.9 miles per hour while Jean cycled at
ehidna [41]

Answer:

Giovanni was 0.5 miles from the finish line

Step-by-step explanation:

This is a problem of movement with constant velocity.

For this kind of problems, generally it is enough to remember the definition of average velocity v:

v=\frac{x}{t}

Where x is the change in position that took place in an interval t.

First, find the time that Jean, who cycled at 24 miles per hour, spent on the race:

Isolating t from the last equation,

t=\frac{x}{v}, and replacing the data for Jean movement:

t=\frac{120}{24}=5h

Second, find what was the distance that Giovanni had cycled when Jean crossed the line:

x=v*t\\ x=23.9*5=119.5

When Jean crossed the line he had cycled 120 miles, and Giovanni 119.5; so Giovanni was 0.5 miles from the finish line.

4 0
3 years ago
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