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kati45 [8]
3 years ago
6

Question in picture solve

Mathematics
1 answer:
balandron [24]3 years ago
3 0

Answer:

x int (-3,0) and x int (2,0)

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Graph the equation by translating Y =|x|. Y=|x+1|-3
goldenfox [79]

Answer:

look at the graph i made with desmos, i just plugged the equation in.

Step-by-step explanation:

6 0
3 years ago
Can someone please help me with this problem, it is really confusing
levacccp [35]
Answer =-0.7x +0

Find the gradient by y2-y1/x2-x1
-14 -7/ 20- -10
-21/30
-0.7
And plug in the coordinates to find the y intercept
7= -0.7 (-10) + c
C=0
4 0
3 years ago
The sum of two numbers is less than 10. If we subtract the second number from the first, the difference is greater than 3
alexandr402 [8]

Answer:

im stuck

Step-by-step explanation:

7 0
3 years ago
Under average driving conditions, the life lengths of automobile tires of a certain brand are found to follow an exponential dis
wariber [46]

Answer:

a) P(X>30000)=1-( 1- e^{-\frac{30000}{30000}})=e^{-1}=0.368

b) P(X>30000|X>15000)=P(X>15000)=1-( 1- e^{-\frac{15000}{30000}})=e^{-0.5}=0.607

Step-by-step explanation:

Previous concepts

The exponential distribution is "the probability distribution of the time between events in a Poisson process (a process in which events occur continuously and independently at a constant average rate). It is a particular case of the gamma distribution". The probability density function is given by:

P(X=x)=\lambda e^{-\lambda x}, x>0

And 0 for other case. Let X the random variable that represent "life lengths of automobile tires of a certain brand" and we know that the distribution is given by:

X \sim Exp(\lambda=\frac{1}{30000})

The cumulative distribution function is given by:

F(X) = 1- e^{-\frac{x}{\mu}}

Part a

We want to find this probability:

P(X>30000) and for this case we can use the cumulative distribution function to find it like this:

P(X>30000)=1-( 1- e^{-\frac{30000}{30000}})=e^{-1}=0.368

Part b

For this case w want to find this probability

P(X>30000|X>15000)

We have an important property on the exponential distribution called "Memoryless" property and says this:

P(X>a+t| X>t)=P(X>a)  

On this case if we use this property we have this:P(X>30000|X>15000)=P(X>15000+15000|X>15000)=P(X>15000)

We can use the definition of the density function and find this probability:

P(X>15000)=1-( 1- e^{-\frac{15000}{30000}})=e^{-0.5}=0.607

7 0
3 years ago
Which function defines the sequence 7,4,1,-2,-5... where f(8)=-14
Ronch [10]

Answer:

f(x)= -3x+10

Step-by-step explanation:

5 0
3 years ago
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