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evablogger [386]
3 years ago
6

Suppose your​ friend's parents invest $15,000 in an account paying 5% compounded annually. What will the balance be after 10 ​ye

ars?
Mathematics
1 answer:
Bad White [126]3 years ago
8 0

Answer:

ofofxotdurz8sues8re8r8zirrizririzrir9

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An investment of $8,000 earns interest at an annual rate of 7% compounded continuously. Complete parts (A) and (B) below. Click
Sergeeva-Olga [200]

Answer:

A.    \mathtt{\dfrac{dA}{dt}|_{t=2}=644.15}

B.    \mathtt{\dfrac{dA}{dt}|_{t = 5.79}= 839.86 }

Step-by-step explanation:

Given that:

An investment of  Amount = $8000

earns  at an annual rate of interest = 7% = 0.07 compounded continuously

The objective is to :

A)  Find the instantaneous rate of change of the amount in the account after 2 year(s).

we all know that:

A = Pe^{rt}

where;

A = (8000) \ e ^{0.7t}

The instantaneous rate of change = \dfrac{dA}{dt}

\dfrac{dA}{dt} = \dfrac{d}{dt}(8000 \ e ^{0.07t} )

= 8000 \dfrac{d}{dt}e^{0.07 \ t}

\dfrac{dA}{dt}= 8000 (0.07)e^{0.07 \ t}

\dfrac{dA}{dt}= 560 e^{0.07 \ t}

At t = 2 years; the instantaneous rate of change is:

\dfrac{dA}{dt}|_{t=2}= 560 e^{0.07 \times 2}

\mathtt{\dfrac{dA}{dt}|_{t=2}=644.15}

(B) Find the instantaneous rate of change of the amount in the account at the time the amount is equal to $12,000.

Here the amount = 12000

12000 = (8000)e^{0.07 \ t}

\dfrac{12000 }{8000}= e^{0.07 \ t}

1.5= e^{0.07 \ t}

㏑(1.5) = 0.07 t

0.405465 = 0.07 t

t = 0.405465 /0.07

t = 5.79

\dfrac{dA}{dt}= 560 e^{0.07 \ t}

At t = 5.79

\dfrac{dA}{dt}|_{t = 5.79}= 560 e^{0.07 \times 5.79}

\mathtt{\dfrac{dA}{dt}|_{t = 5.79}= 839.86 }

7 0
3 years ago
Help me please thank you
Nezavi [6.7K]
Answer is 28 units because it’s 15 over 42 is equal to 10 over “x”, then you cross multiple which you end up with 15x=420 divide 420 from 15 which equals 28.
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Pie
3x+4 = 5x+22
-5x -5x

-2x+4 = 22
-4 -4

-2x = 18

x= -9
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It took mina 3hours to knit 3/4 of a scarf. How many hours will it take her to knit 1 scarf
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Step-by-step explanation:

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Simplify this Algebraic equation with steps<br> -6q +7 -2 +4q
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-6q +7 -2 +4q

Combine like terms

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