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user100 [1]
2 years ago
13

Find the value of c that makes t – 22t+c a perfect square trinomial.

Mathematics
1 answer:
Verizon [17]2 years ago
7 0

Answer:

c = 121

Step-by-step explanation:

Given

t² - 22t

To complete the square

add ( half the coefficient of the t- term )² to t² - 22t

= t² + 2(- 11)t + (- 11)²

= t² - 22t + 121

with c = 121

Thus

t² - 22t + 121 = (t - 11)²

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There are more swimmers under 30 years old than there are age 50 and above.
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Answer:

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Step-by-step explanation:

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It appears that people who are mildly obese are less active than leaner people. One study looked at the average number of minute
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Answer:

Obese people

Lower = \mu - 2\sigma = 373- 2(67) = 239

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Lower = \mu - 2\sigma = 526- 2(107) = 312

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Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

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Solution to the problem

Obese people

Let X the random variable that represent the minutes of a population (obese people), and for this case we know the distribution for X is given by:

X \sim N(373,67)  

Where \mu=373 and \sigma=67

On this case we know that 95% of the data values are within two deviation from the mean using the 68-95-99.7 rule so then we can find the limits liek this:

Lower = \mu - 2\sigma = 373- 2(67) = 239

Upper = \mu + 2\sigma = 373+ 2(67) = 507

Lean People

Let X the random variable that represent the minutes of a population (lean people), and for this case we know the distribution for X is given by:

X \sim N(526,107)  

Where \mu=526 and \sigma=107

On this case we know that 95% of the data values are within two deviation from the mean using the 68-95-99.7 rule so then we can find the limits liek this:

Lower = \mu - 2\sigma = 526- 2(107) = 312

Upper = \mu + 2\sigma = 526+ 2(107) = 740

The interval for the lean people is significantly higher than the interval for the obese people.

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2 years ago
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