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Luba_88 [7]
3 years ago
12

Write the equation of a line in slope-intercept form, that is parallel to the line 3y = 5x - 8 .

Mathematics
1 answer:
Norma-Jean [14]3 years ago
5 0

Answer:

y = \frac{5}{3}x + \frac{8}{3}

Step-by-step explanation:

y = mx + b

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If 3/4y=6-1/3c then what is the value of 2c+9/2y
rosijanka [135]

Answer:

36

Step-by-step explanation:

3/4y=6-1/3c

3/4y+1/3c=6

multiplied 6 into equation to get 2c

9/2y+2c=36

so 2c+9/2y=36

4 0
3 years ago
Explain how you would find the least impossible number of rows in the auditorium
Anna007 [38]
You would find the least possible rows in the auditorium by multiplying 8 by 70 and the answer would be 560 seats in the auditoturim. This would be correct because Kayla knows that there are at least 70 rows (the least amount of rows).

I hope this helped you 

4 0
3 years ago
Solve this equation: x+21=20​
____ [38]

Answer:

x=20-21

x= -1

hope helps... :)

5 0
3 years ago
Read 2 more answers
Three boys and six girls are being seated in a row of nine chairs on a stage which are numbered from left to right. How many sea
OLga [1]

Answer:

A. 362,880

B. 4,320

C. 14,400

D. 21,600

Step-by-step explanation:

A.

If there are no restrictions as to how they are seated, then we have permutations of 9 elements and there are 9! (factorial of 9) = 362,880 different seating arrangements.

B.  

If the boys sit in the middle three seats, they can sit in 3!=6 different ways, the girls can sit then in 6!=720 different ways. By the fundamental rule of counting, there are 6*720 = 4,320 different seating arrangements.

C.

We now have arrangements of the type

g, g, x, x, x, x, x, x, g  

The three girls at the ends can be chosen in C(6;3) (combinations of 6 taken 3 at a time) =  

\large \frac{6!}{3!(6-3)!}=\frac{6!}{3!3!}=20

different ways. The 6 in the middle can be sit in 6!=720 different ways.

By the fundamental rule of counting, there are 20*720 = 14,400 different seating arrangements.

D.

Now we have arrangements

g,b,g,b,x,x,x,x,x

For the 1st position we have 6 possibilities, for the 2nd we have 3 possibilities, for the 3rd we have 5 possibilities and for the 4th we have 2 possibilities. For the last 5 we have 5!=120 possibilities.

By the fundamental rule of counting, there are 6*3*5*2*120 = 21,600 different seating arrangements.

3 0
4 years ago
Andrew has a bag with an equal number of yellow and orange jelly beans. He draws a tree diagram to show the sample space if he r
PSYCHO15rus [73]
He has 2 jelly beans
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3 years ago
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