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aalyn [17]
2 years ago
9

drag a series of transformations of trapezoid ABCD to the table that show trapezoid ABCD is congruent to trapezoid EFGH​

Mathematics
1 answer:
12345 [234]2 years ago
6 0

Answer: Reflect Y-Axis & 10 Units Down

Step-by-step explanation:

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Will give brainiest for this
cluponka [151]

Answer:

lol, u can still ask the question

Step-by-step explanation:

3 0
2 years ago
What and which at time are the maximum and minimum speeds in this function?
Svetach [21]

Answer:

the maximum is 12000 and the minimum is 0

Step-by-step explanation:

sorry if this doesn't answer your question

4 0
3 years ago
Read 2 more answers
Solve the following inequality for d. Write your answer in simplest form.
suter [353]

Answer:

d>67

Step-by-step explanation:

Let's solve your inequality step-by-step.

−50−(−9d+7)>−d+10+9d

Step 1: Simplify both sides of the inequality.

9d−57>8d+10

Step 2: Subtract 8d from both sides.

9d−57−8d>8d+10−8d

d−57>10

Step 3: Add 57 to both sides.

d−57+57>10+57

d>67

8 0
2 years ago
Use the data set below to answer questions 7 to 9
Mariana [72]
Range: 16 (20 - 4)

Median: 9 (average 8 and 10)

Mean: 9.5 (average all the numbers)
8 0
3 years ago
Use a matrix equation to solve the system of linear equations. left brace Start 2 By 1 Matrix 1st Row 1st Column 2nd Row 1st Col
natali 33 [55]

Answer:

\left[\begin{array}{ccc}3&-1&\\-1&1/2\\\end{array}\right]

Step-by-step explanation:

The matrix system for the linear equations: x + 2y = 8, 2x + 6y = 9

\left[\begin{array}{ccc}1&2&\\2&6\\\end{array}\right] \left[\begin{array}{ccc}x\\y\end{array}\right] = \left[\begin{array}{ccc}8\\9\end{array}\right]

To get the coefficient of x and y, the inverse of the first matrix (let the first matrix be A) must be known.

A^{-1} = (1 / determinant of A) x Adjoint of A

the determinant of A = (1 x 6) - (2 x 2) = 6 - 4 = 2

Adjoint of A = \left[\begin{array}{ccc}6&-2&\\-2&1\\\end{array}\right]

A^{-1}= \frac{1}{2} \left[\begin{array}{ccc}6&-2\\-2&1\end{array}\right] = \left[\begin{array}{ccc}3&-1&\\-1&1/2\\\end{array}\right]

4 0
2 years ago
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