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Alona [7]
3 years ago
7

Heyy! i’ll give brainliest please help

Mathematics
2 answers:
Crank3 years ago
5 0

Answer:

C

Step-by-step explanation:

THE THIRD CHOICE

gavmur [86]3 years ago
5 0

Answer: I would say B is the answer because you should never capitalize those directions

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Math
lozanna [386]

Answer:

1. x=6

2. C <-26

3. p<6

4. -5x-44

Step-by-step explanation:

1. 2x = 3(x-2) - 3(x-6)

Distribute

2x= 3x-6 -3x+18

Combine like terms

2x =12

Divide by 2

2x/2 =12/2

x=6


2. C+6<-20

   Subtract 6 from each side

C+6-6 < -20-6

C <-26


3. -5p > -30  

Divide by -5.  Remember to flip the inequality when dividing by a negative

-5p/-5 < -30/-5

p<6


4. -4 - 5(X+8)

Distribute

-4 -5x-40

Combine like terms

-5x-44

6 0
4 years ago
Hlep plsi need bro im am stuck
Marta_Voda [28]

Answer:

its an enlargment

Step-by-step explanation: ur welcome :)

4 0
3 years ago
Evaluate the expression: m-3n when m=8, n=2<br><br> A. 10<br> B. 2<br> C. 14<br> D. 13
kvv77 [185]
I think it’s B. 2

8-3(2)
6 0
4 years ago
Read 2 more answers
All the radii of a circle have the same length? True or False
Semenov [28]

The answer to your question is true

3 0
3 years ago
Read 2 more answers
In Exercise,find the horizontal asymptote of the graph of the function.<br> f(x) = 8x^3+2/2x^3+x
KIM [24]

Answer:

Horizontal asymptote of the graph of the function f(x) = (8x^3+2)/(2x^3+x) is at  y=4

Step-by-step explanation:

I attached the graph of the function.

Graphically, it can be seen that the horizontal asymptote of the graph of the function is at y=4. There is also a <em>vertical </em>asymptote at x=0

When denominator's degree (3) is the same as the nominator's degree (3) then the horizontal asymptote is at (numerator's leading coefficient (8) divided by denominator's lading coefficient (2))  y=\frac{8}{2}=4

6 0
3 years ago
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