2 years ago

May someone possibly help me please

Mathematics

1 answer:

nekit [7.7K]2 years ago

5 0

Answer:

24____________________

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Find x and y. Please write your answer in simplified radical form.

scoray [572]

Answer:

see explanation

Step-by-step explanation:

Using the sine and cosine ratios in the right triangle

sin30° = $\frac{opposite}{hypotenuse}$ = $\frac{6}{y}$

Multiply both sides by y

y × sin30° = 6 ( divide both sides by sin30° )

y = $\frac{6}{sin30}$ = $\frac{6}{\frac{1}{2} }$ = 12

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cos30° = $\frac{adjacent}{hypotenuse}$ = $\frac{x}{y}$

Multiply both sides by y ( y = 12 )

12 × cos30° = x

x = 12 × $\frac{\sqrt{3} }{2}$ = 6 $\sqrt{3}$

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Dennis_Churaev [7]

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geniusboy [140]

Answer:

∠LOA≅∠LMA

Step-by-step explanation:

The first two options are incorrect because you need one more set of congruent ANGLES, not SIDES. The last option would prove congruency, but through ASA, not AAS. So it would be the third option.

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