Answer:
<h2>
-3</h2>
Solution,
![\frac{24 {x}^{2} + 25x - 47}{ax - 2} = - 8x - 3 - \frac{53}{ax - 2} \\ \frac{24 {x}^{2} + 25x - 47 }{ax - 2} = \frac{( - 8x - 3)(ax - 2) - 53}{ax - 2} \\ 24 {x}^{2} + 25x - 47 = - 8a {x}^{2} + (16 - 3a)x - 47 \\](https://tex.z-dn.net/?f=%20%5Cfrac%7B24%20%7Bx%7D%5E%7B2%7D%20%20%2B%2025x%20-%2047%7D%7Bax%20%20-%202%7D%20%20%3D%20%20%20-%208x%20-%203%20-%20%20%5Cfrac%7B53%7D%7Bax%20-%202%7D%20%20%5C%5C%20%20%5Cfrac%7B24%20%7Bx%7D%5E%7B2%7D%20%2B%2025x%20-%2047%20%7D%7Bax%20-%202%7D%20%20%3D%20%20%5Cfrac%7B%28%20-%208x%20-%203%29%28ax%20-%202%29%20-%2053%7D%7Bax%20-%202%7D%20%20%5C%5C%2024%20%7Bx%7D%5E%7B2%7D%20%20%2B%2025x%20-%2047%20%3D%20-%208a%20%7Bx%7D%5E%7B2%7D%20%20%2B%20%2816%20-%203a%29x%20-%2047%20%5C%5C%20)
Equating coefficients from both side:
![- 8a = 24 \\ a = \frac{ 24}{ - 8} \\ a = - 3](https://tex.z-dn.net/?f=%20-%208a%20%3D%2024%20%5C%5C%20a%20%3D%20%20%5Cfrac%7B%20%2024%7D%7B%20-%208%7D%20%20%5C%5C%20a%20%3D%20%20-%203)
Hope this helps..
good luck on your assignment..
M is located in Quadrant II, the line BD has a midpoint located in Quadrant II, AD has a midpoint at the origin.
Answer:
it does not have the steps but the answer is 52.
Step-by-step explanation:
Answer:
![\text{Equation of parabola is }y^2=-12x](https://tex.z-dn.net/?f=%5Ctext%7BEquation%20of%20parabola%20is%20%7Dy%5E2%3D-12x)
Step-by-step explanation:
We need to find the equation of parabola using given information
- Vertex: (0,0)
- Open to the left
- Focal width = 12
If parabola open left and passes through origin then equation is
![y^2=-4ax](https://tex.z-dn.net/?f=y%5E2%3D-4ax)
Focal width = 12
Focal width passes through focus and focus is mid point of focal width.
Focus of above parabola would be (-a,0)
Passing point on parabola (-a,6) and (-a,-6)
Now we put passing point into equation and solve for a
![6^2=-4a(-a)](https://tex.z-dn.net/?f=6%5E2%3D-4a%28-a%29)
![a=\pm 3](https://tex.z-dn.net/?f=a%3D%5Cpm%203)
a can't be negative.
Therefore, a=3
Focus: (-3,0)
Equation of parabola:
![y^2=-12x](https://tex.z-dn.net/?f=y%5E2%3D-12x)
Please see the attachment of parabola.
![\text{Thus, Equation of parabola is }y^2=-12x](https://tex.z-dn.net/?f=%5Ctext%7BThus%2C%20Equation%20of%20parabola%20is%20%7Dy%5E2%3D-12x)
Red line
slope m = 1/4
y=(1/4)x+b
b is y-intercept, b=1
y=(1/4)x+1
To get it the for that are given in the problem multiply both sides by 4.
4y=x+4, or x-4y=-4 red line
blue line
slope m=-3/4
y-intercept b= 9
y=-(3/4)x+9
4y=-3x+36
3x+4y=36 blue line
x-4y=-4 red line
3x+4y=36 blue line
<span>A) x − 4y = −4, 3x + 4y = 36 </span>