Answer:
and as 
Step-by-step explanation:
Given
-- Missing from the question
Required
The behavior of the function around its vertical asymptote at 

Expand the numerator

Factorize

Factor out x + 1

We test the function using values close to -2 (one value will be less than -2 while the other will be greater than -2)
We are only interested in the sign of the result
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As x approaches -2 implies that:
Say x = -3


We have a negative value (-12); This will be called negative infinity
This implies that as x approaches -2, p(x) approaches negative infinity

Take note of the superscript of 2 (this implies that, we approach 2 from a value less than 2)
As x leaves -2 implies that: 
Say x = -2.1

We have a negative value (-56.1); This will be called negative infinity
This implies that as x leaves -2, p(x) approaches negative infinity

So, the behavior is:
and as 