3 years ago

Please help me thanks

Mathematics

1 answer:

Helga [31]3 years ago

5 0

Answer:

C. 1/6

Step-by-step explanation:

hope it helps

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marusya05 [52]

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4)Subtract 27 from both sides
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3 years ago

Which number is prime? 36,38,37,35

Phantasy [73]

I think its 37 bc 2 goes in to 36, and 38, and 5 goes into 35 but nothing goes into 37

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4 years ago

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lara [203]

Since order is important...

12!/(12-3)!=1320

or if you prefer

12*11*10=1320

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3 years ago

The circle given by : x^2 + y^2 - 6y - 12 = 0 can be written as:

deff fn [24]

Step-by-step explanation:

Given equation of circle is,

${x}^{2} + {y}^{2} - 6y - 12 = 0 \\ by \: compairing \: it \: with \: \\ {x}^{2} + {y}^{2} + 2gx + 2fy = 0 \: we \: get \\2 g = 0 \: or \: g = 0 \\ 2f= - 6 \\ or \: f= - 3 \\ c = - 12$

again the another form of circle is,

${x}^{2} + {(y - k)}^{2} = 21 \\ or \: {x}^{2} + {y}^{2} - 2ky + {k}^{2} - 21 = 0 \\ by \: compairing \:it \: with \: \\ {x}^{2} + {y}^{2} + 2gx + 2fy = 0 \: we \: get \\ g = 0 \\f = - k \\ c = {k}^{2} - 21$

now equating the values of f in both equations,

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therefore k=3

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3 years ago

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Arada [10]

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4 years ago