Answer:Assuming all three, we shall find that each of the relations in 3:14 leads to a ... Then by 3:15 the relations AD//BC and AB||DE imply AD//CE, which excludes ... From 2:72, 3:11, 3:14, and 3:16 we deduce 3:19 If A, B, C are three distinct ... a point D lies between X and Y in AB/C if it belongs to XY/C, that is, if XY||CD
Step-by-step explanation:
Answer:
Gareth has a deck of cards with 12 challenge cards and 8 prize cards.
=> The probability he selects a prize card: P = 8/(12 + 8) = 8/20 = 0.4
Gareth is going to randomly select a card from the deck 148 times, replacing the card and shuffling the deck after each selection .
=>The randomness is kept same for all selecting times
Then the best prediction for the number of times Gareth will select a prize card:
=> N = 0.4 x 148 = 59.2 = 59 times
Hope this helps!
:)
Answer:
K
Step-by-step explanation:
By altering the initial height, you change the h-intercept. That will affect the maximum height and the t-intercept.
Answer: K
IQR = 40
1) Put the numbers in order: 40, 45, 50, 60, 60, 75, 90, 90, 120
2) Find the median: Median is 60 (the 2nd one)
3) Place parentheses around the numbers above and below the median. For easy identification of Q1 and Q3. (40, 45, 50, 60,) 60, (75, 90, 90, 120)
4) Find the Q1 and Q3. Q1 = median of the lower half of the data; Q3 = median of the higher half of the data. Q1 and Q3 have even sets so its median cannot be defined.
5) Had both sets contain odd sets, the median of Q1 is subtracted from the median of Q3 to get the IQR.
We can then use the Alternative definition of IQR.
IQR is the difference between the largest and smallest values in the middle 50% of a set data.
40, 45, 50, 60, 60, 75, 90, 90, 120
Middle 50% is 50, 60, 60, 75, 90; IQR = Largest value - smallest value;
IQR = 90 - 50 = 40
