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ziro4ka [17]
3 years ago
11

Please help plsplspslspl

Mathematics
2 answers:
NNADVOKAT [17]3 years ago
7 0
39 will be your answer
Alenkasestr [34]3 years ago
5 0

Answer:it is 39

Step-by-step explanation:

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Please please i beg for help omg
Mice21 [21]
The goal is to make the bases the same and so 27 can become 3^3
3^5x = 3 ^ 3(2x-4)
This becomes
3^5x= 3 ^6x-12
Now that the bases are the same, set the exponents equal to one another
5x= 6x-12
Subtract 6x on both sides
-x= -12
Divide -1 on both sides
X=12
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Find two consecutive whole numbers that 18 lies between
grin007 [14]

if they are even consecutive then it is 16 and 20

if they are odd the it is 17 and 19

3 0
3 years ago
Factor polynomial 4a^2-4a+1
WARRIOR [948]

Answer:

(2a−1)(2a−1)

Step-by-step explanation:

Factor 4a2−4a+1

4a2−4a+1

=(2a−1)(2a−1)

3 0
4 years ago
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Make and test a conjecture about the given quantity.
larisa [96]

Answer:

18. The conjecture is: The product of two negative even integers is an even integer.

Testing: Let integers be -4 and -6. [Two negative even integers]

Then (-4) × (-6) = 24 [Even integer]

19. The conjecture is: Sum of two negative odd integers is a negative even integer.

Testing: Let the two negative odd integers be -3 and -7.

Then -3 + (-7) = -10 is a negative even integer

20. The conjecture is: Sum of two even integers and two odd integers is an even integer.

Testing: Let integers be 4, 12, 13, 17 (Two even integers and two odd integers)

Then 4 + 12 + 13 + 17 = 46 (Even integer)

21. The statement is:  p------->q [If you ran 1 mile, then you ran 5280 feet]

Decide whether statement is true: So if p is True then q is also True.

Hence p------->q is True. So the given statement is True.

Step-by-step explanation:

18. The product of two negative even integers.

Let the integers be -2m and -2n, m and n are positive integers

Product in (-2m) × (-2n) = 4mn = 2(2mn)

= 2p, p = 2mn

The conjecture is: The product of two negative even integers is an even integer.

Testing: Let integers be -4 and -6. [Two negative even integers]

Then (-4) × (-6) = 24 [Even integer]

19. The sum of two negative odd integers.

Let the integers be -(2m + 1) and -(2n + 1), m and n are positive integers

Then -(2m + 1) + [-(2n + 1)] = -2m - 1 - 2n - 1

= -2m - 2n - 2

= -2(+m + 2 + 1)

= -2p, p = m + n + 1

The conjecture is: Sum of two negative odd integers is a negative even integer.

Testing: Let the two negative odd integers be -3 and -7.

Then -3 + (-7) = -10 is a negative even integer

20. The sum of two even integers and two odd integers.

Let the integers be 2m, 2n, 2p + 1, 2q + 1 (m, n, p, q are positive integers)

Then, 2m + 2n + 2p + 1 + 2q + 1 = 2(m + n + p + q + 1)

= 2r, r = m + n + p + q + 1

The conjecture is: Sum of two even integers and two odd integers is an even integer.

Testing: Let integers be 4, 12, 13, 17 (Two even integers and two odd integers)

Then 4 + 12 + 13 + 17 = 46 (Even integer)

21. Let p: You ran 1 mile

Let q: You 5280 feet

The statement is:  p------->q [If you ran 1 mile, then you ran 5280 feet]

Since 1 mile = 5280 feet

So if p is True then q is also True.

Hence p------->q is True. So the given statement is True.

6 0
3 years ago
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