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snow_tiger [21]
3 years ago
6

Need help with a simple problem 2^x=3^x+1

Mathematics
1 answer:
KiRa [710]3 years ago
4 0
For x\ \textgreater \ 0, 2^x\ \textless \ 3^x, all the more 2^x\ \textless \ 3^x+1, therefore no solution.

For x=0, we have 2^0=3^0+1 \Rightarrow 1=1+1 \Rightarrow 1=2. Obviously that' false.

For x\ \textless \ 0 both 2^x and 3^x, where 2^x\ \textgreater \ 3^x, belong to the range (0,1), then 3^x+1 belong to the range (1,2).
Those ranges don't have a common part, therefore, again, no solution.

So, the equation 2^x=3^x+1 doesn't have a solution.

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What is the value of x?
Alisiya [41]
Simplify the first numerator first
-2(x+1)
-2x-2

Then you can set up an equation using cross multiplication
5(-2x-2)= 3x

Simplify and solve
-10x-10=3x
-10=13x
-10/13=x

Final answer: x=-10/13
3 0
3 years ago
A ball is thrown with an initial velocity of 70 km per second, at an angle  of 35° with the horizontal. Find the vertical and ho
oksian1 [2.3K]

Answer:

i. The horizontal component of the ball = 15.8

ii. The vertical component of the ball = 11.2

Step-by-step explanation:

A thrown ball is an example of a projectile, whose motion can be explained with respect to both horizontal and vertical components.

Horizontal component of the ball = U Cos θ

Vertical component of the ball = U Sin θ

where U is the initial velocity of the ball, and θ is the angle of projection.

Thus for the given question,

U = 70 km/hr (19.44 m/s)

θ = 35°

So that;

i. The horizontal component of the ball = 19.44 Cos 35°

                                               = 19.44 x 0.8192

                                               = 15.785

The horizontal component of the ball = 15.8.

ii. The vertical component of the ball = 19.44 Sin 35°

                                                = 19.44 x 0.5736

                                                = 11.151

The vertical component of the ball = 11.2

5 0
3 years ago
Find the 12th and 37th term for each arithmetic sequence.
shutvik [7]

Answer:

  3.  f(12) = -10; f(37) = -60

  4.  f(12) = -102; f(37) = -352

Step-by-step explanation:

3. Put the numbers in the formula and do the arithmetic:

  f(12) = 12 -2(12-1) = 12 -22 = -10

  f(37) = 12 -2(37-1) = 12 -72 = -60

__

4. The explicit formula for an arithmetic sequence with first term a1 and common difference d is ...

  an = a1 +d(n -1)

Your sequence has a first term a1=8 and a common difference d=-10.

As above, fill in the numbers and do the arithmetic.

  f(12) = 8 -10(12 -1) = -102

  f(37) = 8 -10(37-1) = -352

5 0
3 years ago
In the accompanying diagram. altitude CD is
Bogdan [553]

Answer:  √117

Step-by-step explanation:

Since no diagram present, am assuming hypotenuse AB and right angle C.  Let side opp angle B be b, and side opposite angle A be a. Altitude CD is x.

a^2 + b^2 = 22^2 (Pythagorean)

Using Pythag on two smaller triangles,

x^2 + 13^2 = a^2

x^2 + 9^2 = b^2

Substituting in first equation,

x^2 + 13^2 + x^2 + 9^2 = 22^2

x^2 = 117, so x = √117

7 0
3 years ago
Find the value of a and b when x = 12
oksano4ka [1.4K]

Answer:

a=120

b=240

Step-by-step explanation:

if x=12

a=5×2×2×2(x-5)

5×2=10×2×2=40

40(x-5) 40x-200

200=40×\40x=5

b=2×10×12=240

a=120

b=240

7 0
3 years ago
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