We have been given for a normal distribution the mean time it takes to walk to the bus stop is 8 minutes with a standard deviation of 2 minutes. And the mean time it takes for the bus to get to school is 20 minutes with a standard deviation of 4 minutes.
(a) Average time that it would take reach school can be obtained by adding the average times.
8+20 = 28 minutes.
(b) Standard deviation of the trip to school can be found as:

Therefore, standard deviation of the entire trip is 4.47 minutes.
(c) Let us first find z score corresponding to 30 minutes.
We need to find the probability such that 
Therefore, the required probability is 0.67.
(d) If average time to walk to school is 10 minutes, then overall average time for the trip will be 10+20 = 30 minutes.
(e) Standard deviation won't change it will remain 4.47
(f) The new probability will be:


Therefore, probability will be 0.50.
Factor using the AC method...
The answer is:
(x+6) (x+8)
For x = -3, <span>(-0.7x) equals (-0.7[-3]), or 2.1.
8 8 8
Then f(-3) = ------------------- = ---------------- = ------------ = 0.31 (approx)
1 + 3*e^2.1 1 + 24.499 25.5</span>
Answer:
tôi không hiểu bạn nói gì
Step-by-step explanat ion :
First of all we have to arrange the data in ascending order as shown below:
28, 40, 43, 43, 45, 50, 50
Total number of values = 7
Since the number of values is odd, the median will be the middle value i.e. 4th value which is 43. Median divides the data in two halves:
1st Half = 28, 40, 43
2nd Half = 45, 50, 50
Q1 or the First Quartile is the middle value of the lower or 1st half which is 40.
Q3 or the Third Quartile is the middle value of the upper or second half, which is 50.
IQR or the Inter Quartile Range is the difference of Q3 and Q1.
So, IQR= Q3 – Q1 = 50 – 40 = 10
Thus, IQR for the given data is 10