<span>The domain of the function can be obtained by pluging the values of the range into f(x), i.e domain = {k^2 + 2k + 1 = 25, k^2 + 2k + 1 = 64} = {k^2 + 2k - 24 = 0, k^2 + 2k - 63 = 0}. Solving the two quadratic equations, we have that the range is {-9, -6, 4, 7}.I hope that my answer is helpful! Let me know if you need something more :)</span>
Answer:

Step-by-step explanation:
Here is the full question
A standard piece of paper is 0.05 mm thick. Let's imagine taking a piece of paper and folding the paper in half multiple times. We'll assume we can make "perfect folds," where each fold makes the folded paper exactly twice as thick as before - and we can make as many folds as we want.
Write a function g that determines the thickness of the folded paper (in mm) in terms of the number folds made, n. (Notice that g(0) 0.05,)

The function g has an inverse. The function g⁻¹ determines the number of folds needed to give the folded paper a thickness of t mm. Write a function formula for g⁻¹).
<u>SOLUTION:</u>
If we represent g(n) with t;
Then

Taking logarithm of both sides; we have :

The answer is D
Hope this helps!
If you want a detailed step by step ask me
The solution to the equation is x = 20.
<u>Step-by-step explanation</u>:
The equation is 2( x – 5) = 9 – 3 x + 6 + 8 + 3 x + 7
2x - 10 = 30
2x = 30+10
2x = 40
x = 40/2
x = 20
0.625 dozen
1/12 x 7.5
= 0.625