Ok, so user says that it should be solve for vertex not vertex form
(x,y)
to find the vertex of
y=ax^2+bx+c
the x value of the vertex is -b/2a
the y value is found by plugging in the x value for the vertex back into the original equation and evaluating
y=-2x^2-12x-28
a=-2
b=-12
xvalue of vertex is -(-12)/(2*-2)=12/-4=-3
x value of vertex is -3
plug backin for x
y=-2x^2-12x-28
y=-2(-3)^2-12(-3)-28
y=-2(9)+36-28
y=-18+8
y=-10
yvalue is -10
x value is -3
vertex is (-3,-10)
Answer:
4 2/3
Step-by-step explanation:
8×21=168
168÷36(1 yard in inches)=4 with a remainder of 24
24/36 can both be divided by 12 so its now been reduced to 2/3
Answer:
Solving for t : t=5+2r/5
Solving for r : r=-25/2+5t/2
Step-by-step explanation: Move all of your terms that don't contain r to the right side and solve. Move all terms that don't contain t to the right side and solve.
Hope this helps you out! ☺ I just solved it and I don't have any choices to go off of and so I just solved it. Sorry if it's wrong. ☺
