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3 years ago

Calculate the most probable speed of an ozone molecule in the stratosphere, where the temperature is 270 k.'

1 answer:

8 0

<span>9.672m/s The most probable speed of a molecule at a given temperature is: Vmp=sqrt(2*R*T/M) where R is the gas constant, T is the absolute temperature, and M is the molar mass of the gas. R is 8.314J/(mol*K) T is given as 270K Molar mass must be calculated using the fact that Ozone has 3 oxygen atoms and oxygen has an atomic mass of 15.999. 15.999*3 = 47.997 Plugging this in to the formula gives: sqrt(2*8.314*270/47.997) = sqrt(4489.56/47.997) = 9.672m/s</span>

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2 years ago

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The measures of the three angles of a triangle are given by 18x − 7, 12x + 9, and 4x. What is the measure of the largest angle?

Goryan [66]

Answer:

The greatest angle is $18x-7$

Explanation:

According to angle sum property of a triangle, sum of all the angles of a triangle is equal to $180$ °.

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Therefore,

$18x-7+12x+9+4x=180$ °

$34x+2=180$ °

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$18x-7=18(\frac{89}{17})-7=\frac{1602-119}{17}=\frac{1483}{17}$ ≈ 87.2°

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$4x=4(\frac{89}{17})=\frac{356}{17}$ ≈ 20.9°

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2 years ago

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Varvara68 [4.7K]

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