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den301095 [7]
3 years ago
6

It is 185 mi to fort Worth evang drive 2 hours at 65 miles per hour how far will he be from fort Worth multiply the number of ho

urs times the number of miles per hour
Mathematics
1 answer:
Sophie [7]3 years ago
6 0

Answer:

It is 185 mi to fort Worth evang drive 2 hours at 65 miles per hour how far will he be from fort Worth multiply the number of hours times the number of miles per hour

Step-by-step explanation:

It is 185 mi to fort Worth evang drive 2 hours at 65 miles per hour how far will he be from fort Worth multiply the number of hours times the number of miles per hour

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The population is increasing by 1500 each year  and starts at 1970 population ( = 4800)  so the equation is
y=1500x+4800
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Which expression has a value of 36?
IrinaK [193]

The answer is A or C

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Can you do 2 and 3 please and tell me how you got your answer?
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Answer:

2. Sorry, I don't how to put that into words, because i'm trying to use calculators, then figure out how they got their answer.

3. C

Step-by-step explanation:

2. ^

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The sum of 4.5 and a number K is 26.2​
garri49 [273]

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3 0
2 years ago
Two boats leave the same place at the same time. The first boat heads due north at 10 kilometers per hour. The second boat heads
Maksim231197 [3]

Answer:

18.87 km/hr

Step-by-step explanation:

First boat is heading North with a speed of 10 km/hr.

Second boat is heading West with a speed of 16 km/hr.

Time for which they move = 2.5 hours

To find:

The speed at which the distance is increasing between the two boats.

Solution:

Let the situation be represented by the attached diagram.

Their initial position is represented by point O from where they move towards point A and point B respectively.

Distance = Speed \times Time

Distance\ OA = 10 \times 2.5 = 25\ km

Distance\ OB = 16 \times 2.5 = 40\ km

We can use Pythagorean Theorem to find the distance AB.

AB is the hypotenuse of the right angled \triangle AOB.

According to Pythagorean theorem:

\text{Hypotenuse}^{2} = \text{Base}^{2} + \text{Perpendicular}^{2}\\\Rightarrow AB^{2} = OA^{2} + OB^{2}\\\Rightarrow AB^2 = 25^2 + 40^2\\\Rightarrow AB^2 = 2225^2\\\Rightarrow AB^2 \approx 47.17\ km

The speed at which distance is increasing between the two boats is given as:

\dfrac{47.17}{2.5} \approx 18.87\ km/hr

4 0
2 years ago
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