The formula for total loan cost is attached.
10 years = 120 payments
MONTHLY Interest = .0325 / 12 =
<span>
<span>
<span>
0.0027083333
</span>
</span>
</span>
total = <span>0.0027083333 * 21,000 * 120 / (1-(1</span><span><span>.0027083333)-120
</span>
</span>
total = 6,825 / (1-
<span>
<span>
<span>
0.7228448406
</span>
</span>
</span>
)
total = 6,825 /
<span>
<span>
<span>
0.2771551594
</span>
</span>
</span>
total =
<span>
<span>
<span>
24,625.20
</span>
</span>
</span>
The answer is c for this problem
4 less (-4) 5 times a number (5n) is (=) 11 (11)
-4+5n=11
add 4 to both sides
4-4+5n=11+4
0+5n=15
5n=15
divide both sides by 5
5n/5=15/5
1n=3
n=3
the number is 3
Answer:
The Radius
Step-by-step explanation:
Answer:
![x= -\frac{ln [\frac{5P}{8000-P}]}{0.002}](https://tex.z-dn.net/?f=%20x%3D%20-%5Cfrac%7Bln%20%5B%5Cfrac%7B5P%7D%7B8000-P%7D%5D%7D%7B0.002%7D)
a) ![x= -\frac{ln [\frac{5*200}{8000-200}]}{0.002} =1027.062 \approx 1027](https://tex.z-dn.net/?f=%20x%3D%20-%5Cfrac%7Bln%20%5B%5Cfrac%7B5%2A200%7D%7B8000-200%7D%5D%7D%7B0.002%7D%20%3D1027.062%20%5Capprox%201027)
b) ![x= -\frac{ln [\frac{5*800}{8000-800}]}{0.002} =293.893 \approx 294](https://tex.z-dn.net/?f=%20x%3D%20-%5Cfrac%7Bln%20%5B%5Cfrac%7B5%2A800%7D%7B8000-800%7D%5D%7D%7B0.002%7D%20%3D293.893%20%5Capprox%20294)
Step-by-step explanation:
For this case we have the following function:

We can solve for x like this. First we can reorder the expression like this:



Now we can apply natura log on both sids and we got:
![ln[\frac{40000}{8000-P} -5] = ln e^{-0.002x}](https://tex.z-dn.net/?f=%20ln%5B%5Cfrac%7B40000%7D%7B8000-P%7D%20-5%5D%20%3D%20ln%20e%5E%7B-0.002x%7D)
![ln [\frac{5P}{8000-P}] = -0.002x](https://tex.z-dn.net/?f=%20ln%20%5B%5Cfrac%7B5P%7D%7B8000-P%7D%5D%20%3D%20-0.002x%20)
And if we solve for x we got:
![x= -\frac{ln [\frac{5P}{8000-P}]}{0.002}](https://tex.z-dn.net/?f=%20x%3D%20-%5Cfrac%7Bln%20%5B%5Cfrac%7B5P%7D%7B8000-P%7D%5D%7D%7B0.002%7D)
Part a
For this case we can replace P = 200 and see what we got for x like this:
![x= -\frac{ln [\frac{5*200}{8000-200}]}{0.002} =1027.062 \approx 1027](https://tex.z-dn.net/?f=%20x%3D%20-%5Cfrac%7Bln%20%5B%5Cfrac%7B5%2A200%7D%7B8000-200%7D%5D%7D%7B0.002%7D%20%3D1027.062%20%5Capprox%201027)
Part b
For this case we can replace P = 800 and see what we got for x like this:
![x= -\frac{ln [\frac{5*800}{8000-800}]}{0.002} =293.893 \approx 294](https://tex.z-dn.net/?f=%20x%3D%20-%5Cfrac%7Bln%20%5B%5Cfrac%7B5%2A800%7D%7B8000-800%7D%5D%7D%7B0.002%7D%20%3D293.893%20%5Capprox%20294)