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vesna_86 [32]
3 years ago
14

Treinta y dos ciclistas hacen un viaje de siete días. Cada ciclista requiere 8.33 kg de alimento para todo el viaje. Si cada cic

lista quiere comer la misma cantidad de alimento cada día, ¿cuantos kg de alimentos llevará cargando el grupo al final del día 5
Mathematics
1 answer:
Ghella [55]3 years ago
8 0

Answer:

El grupo al final del día 5 llevará cargando 76.16 kg.

Step-by-step explanation:

Cada ciclista requiere 8.33 kg de alimento para todo un viaje de siete días. Cada ciclista quiere comer la misma cantidad de alimento cada día, por que para determinar la cantidad de comida que consumen cada día se debe dividir la cantidad de comida que requieren para todo el viaje por la duración del viaje:

8.33 kg ÷ 7 días= 1.19 kg por día

Cada ciclista consume 1.19 kg cada día. Entonces, para obtener la cantidad de comida que cada ciclista ha consumido luego de 5 días se debe realizar la multiplicación entre la cantidad de comida consumida en un día por 5 días:

1.19 kg por día* 5 días= 5.95 kg

Entonces, para calcular la cantidad de alimentos que cada ciclista cargará en el quinto día se debe hacer la diferencia entre la cantidad de alimento al principio del viaje y la cantidad de alimento consumida luego de 5 días:

8.33 kg - 5.95 kg= 2.38 kg

La cantidad de alimentos que cada ciclista cargará en el quinto día es 2.38 kg. Entonces, si el grupo contiene 32 ciclistas, la cantidad de alimento que cargará será:

32 ciclistas* 2.38 kg por ciclista= 76.16 kg

<u><em>El grupo al final del día 5 llevará cargando 76.16 kg.</em></u>

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