Count the votes, counting each sophomore ballot as 1.5 votes and each freshmen ballot as 1 vote.
ur doing this because there is 200 more freshmen then sophomores...and if u count each sophomore vote as 1.5, it would make up for the 200 more freshmen
Answer:
Your answer is 23/24
Please give me brainliest if helpful.
<h3>
Answer:</h3>
<u>It squares the amount you scaled it by.</u>
<h3>
Step-by-step explanation:</h3>
For example, imagine that you had 2 by 2 square, and then you put it through a scale factor of 2.
Now each side length would be double of what it once was.
But when you multiply the new lengths together, the area would be of 4 times more.
(Original Equation) 2 * 2 = 4
(Scale Factor of 2) 4 * 4 = 16
So when the scale factor is made, the area would be squared to the multiple that you scaled it by.
<em>***A square root is a number times itself.</em>
<em>(eg): 3 * 3 = </em><em>9</em>
<em> 15 * 15 = </em><em>225</em>
<em>9 and 225 would be the square root in these problems.</em>
Answer:
The 95% confidence interval estimate of the population mean rating for Miami is (6.0, 7.5).
Step-by-step explanation:
The (1 - <em>α</em>)% confidence interval for the population mean, when the population standard deviation is not provided is:
![CI=\bar x \pm t_{\alpha/2, (n-1)}\cdot \frac{s}{\sqrt{n}}](https://tex.z-dn.net/?f=CI%3D%5Cbar%20x%20%5Cpm%20t_%7B%5Calpha%2F2%2C%20%28n-1%29%7D%5Ccdot%20%5Cfrac%7Bs%7D%7B%5Csqrt%7Bn%7D%7D)
The sample selected is of size, <em>n</em> = 50.
The critical value of <em>t</em> for 95% confidence level and (<em>n</em> - 1) = 49 degrees of freedom is:
![t_{\alpha/2, (n-1)}=t_{0.05/2, 49}\approx t_{0.025, 60}=2.000](https://tex.z-dn.net/?f=t_%7B%5Calpha%2F2%2C%20%28n-1%29%7D%3Dt_%7B0.05%2F2%2C%2049%7D%5Capprox%20t_%7B0.025%2C%2060%7D%3D2.000)
*Use a <em>t</em>-table.
Compute the sample mean and sample standard deviation as follows:
![\bar x=\frac{1}{n}\sum X=\frac{1}{50}\times [1+5+6+...+10]=6.76\\\\s=\sqrt{\frac{1}{n-1}\sum (x-\bar x)^{2}}=\sqrt{\frac{1}{49}\times 31.12}=2.552](https://tex.z-dn.net/?f=%5Cbar%20x%3D%5Cfrac%7B1%7D%7Bn%7D%5Csum%20X%3D%5Cfrac%7B1%7D%7B50%7D%5Ctimes%20%5B1%2B5%2B6%2B...%2B10%5D%3D6.76%5C%5C%5C%5Cs%3D%5Csqrt%7B%5Cfrac%7B1%7D%7Bn-1%7D%5Csum%20%28x-%5Cbar%20x%29%5E%7B2%7D%7D%3D%5Csqrt%7B%5Cfrac%7B1%7D%7B49%7D%5Ctimes%2031.12%7D%3D2.552)
Compute the 95% confidence interval estimate of the population mean rating for Miami as follows:
![CI=\bar x \pm t_{\alpha/2, (n-1)}\cdot \frac{s}{\sqrt{n}}](https://tex.z-dn.net/?f=CI%3D%5Cbar%20x%20%5Cpm%20t_%7B%5Calpha%2F2%2C%20%28n-1%29%7D%5Ccdot%20%5Cfrac%7Bs%7D%7B%5Csqrt%7Bn%7D%7D)
![=6.76\pm 2.000\times \frac{2.552}{\sqrt{50}}\\\\=6.76\pm 0.722\\\\=(6.038, 7.482)\\\\\approx (6.0, 7.5)](https://tex.z-dn.net/?f=%3D6.76%5Cpm%202.000%5Ctimes%20%5Cfrac%7B2.552%7D%7B%5Csqrt%7B50%7D%7D%5C%5C%5C%5C%3D6.76%5Cpm%200.722%5C%5C%5C%5C%3D%286.038%2C%207.482%29%5C%5C%5C%5C%5Capprox%20%286.0%2C%207.5%29)
Thus, the 95% confidence interval estimate of the population mean rating for Miami is (6.0, 7.5).
Answer:
the number
the type
Step-by-step explanation: