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vesna_86 [32]
3 years ago
12

I will give u brainliest

Mathematics
1 answer:
Dmitry_Shevchenko [17]3 years ago
3 0

Answer:

1 & 2 = Right Triangles

3 & 4 = Not Right Triangles

Step-by-step explanation:

Solved Using Pythagorean Theorem:

1) 9^{2} + 12^{2} = 225

15^{2} = 225

2) 15^{2} + 36^{2} = 1521

39^{2} = 1521

3) 10^{2} + 26^{2} = 776

28^{2} = 784

4) 10^{2} + 12^{2} = 244

16^{2} = 256

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A company that produces fine crystal knows from experience that 13% of its goblets have cosmetic flaws and must be classified as
Kisachek [45]

Answer:

(a) The probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b) The probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c) The probability that at most five must be selected to find four that are not seconds is 0.9453.

Step-by-step explanation:

Let <em>X</em> = number of seconds in the batch.

The probability of the random variable <em>X</em> is, <em>p</em> = 0.31.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> and <em>p</em>.

The probability mass function of <em>X</em> is:

P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0,1,2,3...

(a)

Compute the probability that only one goblet is a second among six randomly selected goblets as follows:

P(X=1)={6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=6\times 0.13\times 0.4984\\=0.3888

Thus, the probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b)

Compute the probability that at least two goblet is a second among six randomly selected goblets as follows:

P (X ≥ 2) = 1 - P (X < 2)

              =1-{6\choose 0}0.13^{0}(1-0.13)^{6-0}-{6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=1-0.4336+0.3888\\=0.1776

Thus, the probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c)

If goblets are examined one by one then to find four that are not seconds we need to select either 4 goblets that are not seconds or 5 goblets including only 1 second.

P (4 not seconds) = P (X = 0; n = 4) + P (X = 1; n = 5)

                            ={4\choose 0}0.13^{0}(1-0.13)^{4-0}+{5\choose 1}0.13^{1}(1-0.13)^{5-1}\\=0.5729+0.3724\\=0.9453

Thus, the probability that at most five must be selected to find four that are not seconds is 0.9453.

8 0
3 years ago
What is the value of x?
ASHA 777 [7]
The answer is 20

the scale factor is 1.25 (to find that out do 12.5/10) then multiply 16 by 1.25 and you get 20.
7 0
2 years ago
Read 2 more answers
Suppose that x and y vary inversely, and x = 12 when y = 8 . Write the function that models the inverse variation.
Alja [10]

Answer:

y=\frac{96}{x}

Step-by-step explanation:

So when x and y, vary inversely, it means that the product of x and y will remain constant such that: xy=c. This means that the function can be defined as y=\frac{c}{x} by dividing both sides by x. In this case x=12, and y=8, this means the constant is equal to 12 * 8 which is 96. So we have the equation:  xy = 96, which can be defined as y=\frac{96}{x}

7 0
1 year ago
RIDDLE ME THIS Fresh and invigorated after completing her algebra homework, Mimi appeared at the living room door. She held a pi
Marat540 [252]

Answer:

Mimi is 15.

Step-by-step explanation:

Set up two equations, and solve by elimination.

 2(m+5) = d+5

- 3(m-5) =  d-5

_____________

2(m+5) - 3(m-5) = 10

2m + 10 - 3m + 15 = 10

-m + 25 = 10

-m = -15

<u>m = 15</u>

Plug this back in to get dad's age.

2(m+5) = d+5

2(15+5) = d + 5

2(20) = d + 5

40 = d + 5

<u>d = 35</u>

<u></u>

8 0
3 years ago
There are 8 performers who will present their comedy acts this weekend at a comedy club. One of the performers insists on being
Natalija [7]
Well, the keyword here is One of the performers insist on being the last.

So, the amount of performers that we can arrange freely is 7 performers.

Different ways we can schedule their appearance is :

7 ! = 7 x 6  x 5 x 4 x 3 x 2 x 1
   
 
    = 5040

hope this helps
5 0
3 years ago
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