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3 years ago

50 elevens-1 elevens

Mathematics

2 answers:

Tpy6a [65]3 years ago

6 0

Answer:

( 50 -1 ) elevens = 49 elevens = 49 x 11 = 539

50 elevens - 1 elevens = (50 x 11) - (1 x 11)

550 - 11 = 539

kipiarov [429]3 years ago

5 0

Answer:

Step-by-step explanation:

50 elevens-1 elevens = ( 50 -1 ) elevens = 49 elevens

or 49 x eleven = 49 x 11 = _______ (use your calculator here)

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An algebraic expression ,using d as the variable four times a number

larisa [96]

Answer:

Step-by-step explanation:

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4 years ago

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Cells use the hydrolysis of adenosine triphosphate, abbreviated as ATP, as a source of energy. Symbolically, this reaction can b

nataly862011 [7]

Answer:

Step-by-step explanation:

From the given information:

ΔG° = -30.5 kJ/mol

By applying the following equation to calculate the value of K.

ΔG° =-RT㏑K

making ㏑ K the subject of the formula:

$\mathtt{ In \ K} = \dfrac{\Delta G^0}{-RT}$

where;

Temperature at 25° C = (25 + 273)K

= 298K

R = 8.3145 J/mol.K (gas cosntant)

$\mathtt{ In \ K} = \dfrac{-30.5 \times 10^{3}\ J /mol} {-(8.3145 \ J/mol. K \times 298 \ K}$

$\mathtt{ In \ K} = \dfrac{-30.5 \times 10^{3}\ J /mol} {-2477.721 J/mol }$

㏑K = 12.309

$K = e^{12.309}$

K = 221682.17

K = 2.22 × 10⁵

b) The reaction for the metabolism of glucose is given as:

$C_6H_{12} O_6 + 6O_{2(g)} \to + 6CO_{2(g)} + 6H_2O_{(l)}$

From the above expression, let calculate the Gibbs free energy by using the formula:

$\Delta G^0_{rx n }= \Delta G^0_{product}- \Delta G^0_{reactant}$

$\Delta G^0_{rx n }= [6 \times \Delta G^0_{f}(CO_2) + 6 \times \Delta G^0_{f}(H_2O)] - [1 \times \Delta G^0_{f}(C_6H_{12}O_6) + 6 \times \Delta G^0_{f}(O_2)]$

At standard conditions;

The values of corresponding compounds are substituted into the equation above:

Thus,

$\Delta G^0_{rx n }= [6 \times (-394) + 6 \times (-237)] - [1 \times (-911) + 6 \times (0)] \ kJ/mol$

$\Delta G^0_{rx n }= [-2364-1422] - [-911+0] \ kJ/mol$

$\Delta G^0_{rx n }= -3786 +911 \ kJ/mol$

$\Delta G^0_{rx n }= -2875 \ kJ/mol$

$\Delta G^0_{rx n }= -2875000 \ J/mol$

Now, the no of ATP molecules generated = $\dfrac{\Delta G^0 \text{of metabolism for glucose}}{\Delta G^0 \text{of hydrolysis for ATP}}$

= (-2875000 J/mol ) / -30500 J/mol

= 94.26

≅ 94 ATP molecules generated

3 0

3 years ago

Ja'kniya and Alayjah are shopping at the Apple Store. Ja'kniya bought 4 screensavers and 3 Otterboxes for $29. Alayjah bought 6

Katarina [22]

Answer: Each screensaver costs $2 and each Otterbox costs $7.

Step-by-step explanation:

Let x = Cost of each screensaver and y = cost of each Otterbox.

As per given, 4x+3y=29 (i)

6x +2y = 26 (ii)

Divide both sides of (i) by 2 and the multiply it by 3 on sides , we get

9x+3y=39 (iii)

Eliminate (i) from (iii) , we get

5x = 10

⇒ x = 2 [Divide both sides by 5]

Put value of x in (i), we get

4(2)+3y=29

⇒ 8+3y= 29

⇒ 3y= 21

⇒ y =7 [Divide both sides by 7]

Hence, Each screensaver costs $2 and each Otterbox costs $7.

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3 years ago

Solve for r: d = rt

dlinn [17]

D=rt
r=d/t
divide by t to sinlge out r

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3 years ago

What is the perimeter of a square if the is a length of 4x and a width of 36-5x?

yulyashka [42]

4x=36－5x
x=4

The perimeter of the square=4x4×4
=64

7 0

4 years ago