Since segments ST and PQ are parallel, triangles SRT and PRQ are similar due to the AAA postulate. In general, the ratio between the corresponding sides of two similar triangles is constant; therefore,
Furthermore,
Finding PR and RS,
Then,
Solving for PS,
Solve the quadratic equation in terms of PS, as shown below
![\begin{gathered} \Rightarrow PS^2+16PS-132=0 \\ \Rightarrow PS=\frac{-16\pm\sqrt[]{16^2-4(-132)}}{2}=\frac{-16\pm28}{2} \\ \Rightarrow PS=-22,6 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5CRightarrow%20PS%5E2%2B16PS-132%3D0%20%5C%5C%20%5CRightarrow%20PS%3D%5Cfrac%7B-16%5Cpm%5Csqrt%5B%5D%7B16%5E2-4%28-132%29%7D%7D%7B2%7D%3D%5Cfrac%7B-16%5Cpm28%7D%7B2%7D%20%5C%5C%20%5CRightarrow%20PS%3D-22%2C6%20%5Cend%7Bgathered%7D)
And PS is a segment; therefore, it has to be positive.
Hence, the answer is PS=6
Answer:
62.5%
Step-by-step explanation:
im right
Answer:
Step-by-step explanation:
<u>Given system:</u>
<u>Multiply the first equation by 7 and add up the equations:</u>
- -7x + 7y + 7x + 3y = 7*8 - 16
- 10y = 40
- y = 4
<u>Find y:</u>
Answer:
where is the question?
Step-by-step explanation:
Answer:
k = 12h
Step-by-step explanation:
Since each of the inputs of h can be mutiplied by 12 to get the output k, the equation is k = 12h
Hope this helps :)
