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3 years ago

Help please i need the answer quick class ends soon and need a hight grade

Mathematics

2 answers:

Luda [366]3 years ago

8 0

Answer: 14

Step-by-step explanation:

Step 1: Substitute the x and y values:

$\frac{4^3-2^3}{4}$

Step 2: Find 4 to the power of 3.

4 x 4 x 4 = 64

Now find 2 to the power of 3

2 x 2 x 2 = 8

Step 3: Subtract the two values as mentioned in the equation:

64 - 8 = 56

Step 4: Now divide 56 by 4 as mentioned in the equation.

56 ÷ 4 = 14

And... 14 is the answer!

Hope this helps :)

-jp524

stepan [7]3 years ago

7 0

Answer: 14

Step-by-step explanation: LOOK AT MY SCEENSHOT

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In training for a swim meet, Logan swam 750 meters in 1/3 of an hour. His swimming partner Mila, swam 2/3 of Logan's distance in

Brut [27]

Answer:

speed of Logan is 37.5 m/minutes

speed of Milo is 33.33 meters per minutes

Speed of Logan is greater than speed of Milo

difference in speed = 37.5 - 33.33 = 4.17 meters per minutes

Step-by-step explanation:

we will calculate speed in meters per minutes

we know 1 hour = 60 minutes and

1 minutes = 60 seconds

speed = distance/time

____________________________________

For Logan

distance = 750 meters

time = 1/3 of hour = 1/3 *60 minutes = 20 minutes

speed = 750/20 = 37.5 meters per minute

__________________________________________________

For milo

distance = 2/3 of Logan's distance = 2/3 * 750 meters = 500 meters

time = 1/4 of hour = 1/4 *60 minutes =15 minutes

speed = 500/15 = 33.33 meters per minute

Thus, speed of Logan is 37.5 m/minutes

speed of Milo is 33.33 meters per minutes

Speed of Logan is greater than speed of Milo

difference in speed = 37.5 - 33.33 = 4.17 meters per minutes

Step-by-step explanation:

4 0

3 years ago

Four teams A,B,C, and D compete in a tournament, and exactly one of them will win the tournament. Teams A and B have the same ch

beks73 [17]

Answer:

A= 0,2

B= 0,2

C= 0,4

D=0,2

Step-by-step explanation:

We know that only one team can win, so the sum of each probability of wining is one

P(A)+P(B)+P(C)+P(D)=1

then we Know that the probability of Team A and B are the same, so

P(A)=P(B)

And that the the probability that either team A or team C wins the tournament is 0.6, so P(A)+Pc)= 0,6, then P(C)= 0.6-P(A)

Also, we know that team C is twice as likely to win the tournament as team D, so P(C)= 2 P(D) so P(D) = P(C)/2= (0.6-P(A))/2

Now if we use the first formula:

P(A)+P(B)+P(C)+P(D)=1

P(A)+P(A)+0.6-P(A)+(0.6-P(A))/2=1

0,5 P(A)+0.9=1

0,5 P(A)= 0,1

P(A)= 0,2

P(B)= 0,2

P(C)=0,4

P(D)=0,2

4 0

3 years ago

Solve for x in the following figure. Choose the appropriate result.

pickupchik [31]

Answer:

Step-by-step explanation:

all of the angles add up to equal 180 so we setup the equation as 45+3x=180

first you subtract each side by 45

135=3x

then you divide each side by 3 and get that

x=45

8 0

3 years ago

Read 2 more answers

Help I don’t understand at all

zloy xaker [14]

Answer:

$1)\ \ 4h^2-13h+6\\2)\ \ 7x^3y^2-x^2y+1\\3)\ \ -7n+2\\4)\ \ -8m+4$

Step-by-step explanation:

Simplify the expression by combining like terms. Remember, like terms have the same variable part, to simplify these terms, one performs operations between the coefficients. Please note that a variable with an exponent is not the same as a variable without the exponent. A term with no variable part is referred to as a constant, constants are like terms.

$2h^2-7h+2h^2-h+6+4h-9h$

$(2h^2+2h^2)+(-7h-h+4h-9h)+(6)$

$4h^2-13h+6$

Use a very similar method to solve this problem as used in the first. Please note that all of the rules mentioned in the first problem also apply to this problem; for that matter, the rules mentioned in the first problem generally apply to any pre-algebra problem.

$8x^3y^2-7x^2y+8x-4-x^3y^2+2x^2y+4x^2y-8x+5$

$(8x^3y^2-x^3y^2)+(-7x^2y+2x^2y+4x^2y)+(8x-8x)+(-4+5)$

$7x^3y^2-x^2y+1$

Use the same rules as applied in the first problem. Also, keep the distributive property in mind. In simple terms, the distributive property states the following ( $a(b+c)=(a)(b)+(a)(c)=ab+ac$ ). Also note, a term raised to an exponent is equal to the term times itself the number of times the exponent indicates. In the event that the term raised to an exponent is a constant, one can simplify it. Apply these properties here,