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Yuki888 [10]
3 years ago
9

I need help! If you could do a step-by-step explanation, then that would be great.​

Mathematics
1 answer:
sergejj [24]3 years ago
3 0

Answer:

The step by step explanation is given below

Step-by-step explanation:

In Δ INO and Δ GND

\vec{NO} \cong \vec{ND}\ \textrm {given}\\\angle NIO \cong \angle NGD\ \textrm {given}\\\angle INO \cong \angle GND\ \textrm {reflexive}\\\triangle INO \cong \triangle GND\ \textrm {Angle Angle Side test}\\\angle D \cong \angle O\ \textrm {corresponding parts of congruent triangles}

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Agata [3.3K]
The answer is 13 packages.
6 0
3 years ago
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Can anybody help me im super close to failing math
Lady bird [3.3K]

Answer:

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Step-by-step explanation:

-3 1/8 - 2 1/2 is the same as -3 1/2 + -2 1/2

4 0
4 years ago
There are 15 students in the 8th grade. The students are randomly placed into three different algebra classes of 5 students each
xeze [42]

Answer:

The probability is   \frac{6}{91} ≅ 0.0659

Step-by-step explanation:

Let's analyze the question.

There are 15 students in the 8th grade.

The students are randomly placed into three different algebra classes of 5 students each.

We are looking for the probability that Trevor, Terry and Evan will be in the same algebra class.

One possible way to solve this question is to think about the product probability rule.

We can use it because we are in an equiprobable space. (And  also the events are independent).

Let's set for example a class for Evan.

The probability that Evan will be in a class is 1

Then for Terry there are 4 places out of 14 that puts Terry in the Evan's class.

We write 1.\frac{4}{14}

Finally for Trevor there are 3 places out of the remaining 13 that puts Trevor in the same class with Evan and Terry.

Using the product rule we write :

1.\frac{4}{14}.\frac{3}{13}=\frac{6}{91}

The probability of the event is \frac{6}{91} ≅ 0.0659

5 0
4 years ago
How do you solve 2 (5-6) < 8f - 130
irga5000 [103]
2(5-6)<8f-130
(2x5)-(2x6)<8f-130
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128/8<8f/8
16<f
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3 years ago
It takes Amir 4 seconds to run from his front door to the mailbox. If he can run at a top speed of 6.5 m/s, how far is it from h
dlinn [17]
If he runs 6.5 metres per second, then you multiply 6.5 by 4 to get 26m
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