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Answer:</h3>

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Step-by-step explanation:</h3>

The square roots of any perfect squares under the radical can be factored out.
Woohoo
okay, so is z less than or grater than 2/5? greater so you would just label your graph then where ever you put 2/5 you put all the other dots or an arrow going to the right but put an open circle then the arrow something like this
o------------>
(2/5--------->)
sorry if confusing
D. 2,575 yd^2
Hope this helps Issarealqueen! :D
Since the centre is at the origin, (h, k) = (0, 0)
Hence, we can substitute h and k as 0 respectively.
General form:

Now, we know that (0, 4) lies on the circle. Thus, the radius must be 4 units.
So, our circle becomes:

Now, substitute (2, 6) to see if it lies on the circle.

Hence, it doesn't lie on the circle.