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2 years ago

Hi pls help I suck at math

Mathematics

1 answer:

Lelechka [254]2 years ago

5 0

Step-by-step explanation:

93.3

this time will help

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Find the area of the circle. Use 3.14 for it. O d = 10 cm A = [?] cm2 A=Tr2

vazorg [7]

Answer:

i wish i could help. im so bad at math

Step-by-step explanation: good luck

3 0

2 years ago

The diagram shows a rhombus inside a regular hexagon work out the angle x

kvv77 [185]

Answer:

x = 60°

Step-by-step explanation:

The rest of the question is the attached figure.

And it is required to find the angle x.

As shown, a rhombus inside a regular hexagon.

The regular hexagon have 6 congruent angles, and the sum of the interior angles is 720°

So, the measure of one angle of the regular hexagon = 720/6 = 120°

The rhombus have 2 obtuse angles and 2 acute angles.

one of the obtuse angles of the rhombus is the same angle of the regular hexagon.

So, the measure of each acute angle of the rhombus = 180 - 120 = 60°

So, the measure of each acute angle of the rhombus + the measure of angle x = the measure of one angle of the regular hexagon.

So,

60 + x = 120

x = 120 - 60 = 60°

So, the measure of the angle x = 60°

6 0

3 years ago

What is 2/9 divided by 3?

Kryger [21]

((2÷9))÷3
(0.222)÷3
=0.074

3 0

3 years ago

Daisy's teacher asked her class to draw a triangle whose sides measured 2 inches, 3 inches, and 4 inches. She correctly drew the

harina [27]

Answer:

I dont think so since a triangle adds to 180 degrees

Step-by-step explanation:

but im stuck between c and d

sorry I couldnt complete;ly answer it for u!

have a nice day!

4 0

2 years ago

Prove that root 7 is irrational by the method of contradiction

Alchen [17]

Let assume that $\sqrt7$ is a rational number. Therefore it can be expressed as a fraction $\dfrac{a}{b}$ where $a,b\in\mathbb{Z}$ and $\text{gcd}(a,b)=1$ .

$\sqrt7=\dfrac{a}{b}\\\\7=\dfrac{a^2}{b^2}\\\\a^2=7b^2$

This means that $a^2$ is divisible by 7, and therefore also $a$ is divisible by 7.

So, $a=7k$ where $k\in\mathbb{Z}$

$(7k)^2=7b^2\\\\49k^2=7b^2\\\\7k^2=b^2$

Analogically to $a^2=7b^2$ ------- $b^2$ is divisible by 7 and therefore so is $b$ .

But if both numbers $a$ and $b$ are divisible by 7, then $\text{gcd}(a,b)=7$ which contradicts our earlier assumption that $\text{gcd}(a,b)=1$ .

Therefore $\sqrt7$ is an irrational number.

8 0

3 years ago