The hypothesis is given as
H0: μd< 0
H1: μd > 0
<h3>How to solve for the hypothesis.</h3>
The null hypothesis is given as
H0: μd< 0
<h3>The alternative hypothesis is given as </h3>
H1: μd > 0
SWe have to find the value of s
we would use this formula s = sqrt [ (Σ(di - d)^2 / (n - 1) ]
This gives us 3.454
Next we have to determine the standard error
s / √(n)
3.454/2.8284
= 1.22
Degree of freedom = 8 - 1
= 7
t = (x1 - x2) - D / S.E
= 1.025
Find t critical at 0.10
= 1.895
P-value = 0.1697
d. Given that p value is greater thatn 0.1 we fail to reject the null hypothesis.
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Answer:
Sophia gets 7,150
Step-by-step explanation:
Answer:
I think is 53 A
Step-by-step explanation:
The outlier, 78, is removed from the data set shown. 23, 23, 25, 27, 34, 34, 35, 41, 45, 45, 78 How does this affect the range?
KATRIN_1 [288]
Hello.
The range with 78 is 55
without 78 is 22
So the range goes down
Have a nice day
To solve this problem, we need to first find the dimensions of the side of the blue and purple squares.
We're given that the purple (smaller) square has a side length of x inches.
We are also given that the blue band has a width of 5 inches.
Since the blue band surrounds the purple square on both sides, the length of the blue square is x+2(5)=x+10 inches.
The net area of the band is therefore the difference of the area of the blue square and the purple square, namely take out the area of the purple square from the blue.
Therefore
Area of band

[recall



or 20(x+5) if you wish.