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babymother [125]
3 years ago
9

to construct the midpoint of a segment, fold the paper so that the given line segment lies on itself and

Mathematics
2 answers:
Ludmilka [50]3 years ago
5 0
And the endpoints lie on each other.
Tanya [424]3 years ago
5 0

Answer:

The endpoints of the line segment lie on each other

Explanation

To understand the question, follow the practical steps below

1. Take a sheet of plane paper

2. Label the edges of the top of the paper A and B

3. Fold the paper in such a way that edge A lies on B.

You'll notice the following;

1. The top of the paper lies in itself; hence, we can say that the line segment lies on itself

2. You have a new line at the centre of the paper. The point at the top of this center line is the midpoint of the line segment

3. The edges that lie on each other translates to the endpoints lying on each other.

Number (3) above is the required observation and the right answer.

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17. What expression is equivalent to log(200) - log (2)? Calculate the answer.
IRINA_888 [86]

Answer: 2

Step-by-step explanation:

Recall from the laws of Logarithms:

Log a - Log b = Log ( a/b )

That means

Log 200 - Log 2 = Log ( 200/2)

= Log 100 , which could be written as

Log 10^{2}

Recall from laws of Logarithms:

Log a^{b} = b Log a

Therefore:

Log10^{2} = 2 Log 10

Also from law of Logarithm

Log 10 = 1

Therefore 2 Log 10 = 2 x 1

= 2

3 0
3 years ago
You are a traffic accident investigator. You have arrived at the scene of an accident. Two trucks of equal mass (3,000 kg each)
Kazeer [188]

Answer:

1) Kinetic energy of the truck 1 is 600,000 joules.

Kinetic energy of the truck 2 is 1,837,500 joules.

2 a)Potential energy of truck 1 is 646,800 Joules.

b) Energy lose by the truck 1 just got converted into heat and sound energy during the collision.

Step-by-step explanation:

Mass of the truck 1 and truck 2,m = 3000 kg

Velocity of the truck 1, v_1 = = 20 m./s

Velocity of the truck 2,v_2 = 35 m./s

1. Kinetic energy of the truck 1:\frac{1}{2}mv_{1}^2=\frac{1}{2}\times 3000 kg\times (20 m/s)^=600,000 joules

Kinetic energy of the truck 2:\frac{1}{2}mv_{2}^2=\frac{1}{2}\times 3000 kg\times (35 m/s)^=1,837,500 joules

2.a) Energy loose by the truck 1:

Initial height of the truck on the hill = 22 m

At that height potential energy will be maximum:

Potential energy of truck 1 at that height = mgh=3000\times 9.8 m/s^2\times 22 m=646,800 Joules

b) Energy lose by the truck 1 just got converted into heat and sound energy during the collision.

3 0
3 years ago
I need help with my math
Tresset [83]
What is the question 
3 0
3 years ago
Where are the minimum and maximum values for f(x) = -2 + 4 cos x on the interval (0,21]?
Dafna11 [192]

Answer:

Step-by-step explanation:

Maximum value is when cos x = 1

So it is -2 + 4(1) = 2.

Minimum value, when  cos x = -1:

= -2  + 4(-1) = -6.

4 0
3 years ago
Read 2 more answers
The actual distance between two villages is 120 kilometers. On a map of the area, 0.5 centimeter represents 2 kilometers.
stira [4]

Answer:

30 centimeters

Step-by-step explanation:

120 ÷2 =60 now you must use only .5 of that number so you have thirty

3 0
2 years ago
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