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Strike441 [17]
2 years ago
5

Please help Thank yoy

Mathematics
2 answers:
BabaBlast [244]2 years ago
7 0

Answer:

I think its graph 4

Step-by-step explanation:

QveST [7]2 years ago
3 0

Answer:

i believe is graph 1.

Step-by-step explanation:

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Given (64y^2)+(4x^2)+128y+16x+64=0, transform the equation into the appropriate form
____ [38]

Answer:

(8y+8)²+(4x²+16)=0

Step-by-step explanation:

Given:

(64y²)+(4x²)+128y+16x+64=0

Find:

Equation into the appropriate form

Computation:

(64y²)+(4x²)+128y+16x+64=0

(8y)²+(2x)²+128y+16x+64=0

(8y)²+(2x)²+2(8y)(8)+2(2x)(4) + 8²=0

(8y+8)²+(4x²+16)=0

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3 years ago
If morgan spende 17.50 on gas
ehidna [41]
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3 years ago
(-3, 4) and (7.-2)<br> Find slope between the points
navik [9.2K]

Answer:

m=-3/5

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Question Progress
Bess [88]
(x+2)(x+1) = x^2 + x + 2x + 2

simplify it
x^2 + 3x + 2
5 0
2 years ago
The vertices of polygon ABCD are at A(1, 1), B(2, 3), C(3, 2), and D(2, 1). ABCD is reflected across the x-axis and translated 2
lys-0071 [83]

Answer:

  • A^\prime is at (1, \, 1).
  • B^\prime is at (2, \, -1).
  • C^\prime is at (3,\, 0).
  • D^\prime is at (2, \, 1).

Step-by-step explanation:

To reflect a shape about the x-axis, simply reflect each of its vertex across the x-axis.

The y-coordinate of a point gives the vertical position of the point. On the other hand, the x-axis is horizontal. Reflecting the point would invert the y-coordinate of that point.

For example, reflecting B(2,\, 3) about the x-axis would give (2, \, -3).

Similarly, to move the polygon up by 2 units, simply move every one of its vertex up by 2 units. Keep in mind that the order of the translation does matter. In this question, reflect each point before moving them upward.

To move a point up by 2 units, simply 2 to its y-coordinate. Aftering moving (2, \, -3), the reflection of B, up by two units, the new point would have coordinates (2, \, -1).

\begin{array}{cccccc} & \text{Initial} & & \text{After Reflection} & & \text{After translation} \cr A: & (1,\, 1) & \longrightarrow & (1,\, -1) & \longrightarrow & (1,\, 1) \cr B: & (2, \,3) & \longrightarrow & (2,\, -3) & \longrightarrow & (2, \, -1) \cr C: & (3, \,2) & \longrightarrow & (3, \, -2) & \longrightarrow & (3, \, 0) \cr D: & (2, \, 1) & \longrightarrow & (2, \, -1) & \longrightarrow & (2,\, 1) \end{array}.

6 0
3 years ago
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