Answer:
angle AJG equals 59 degrees
Step-by-step explanation:
Answer:
below :)
Step-by-step explanation:
1) 12
2}3/2
3)224.64
4)2 quarters
5)w=50
6)m=6y+7
7)42/6=7 x=6
<h3>
Answer: angle T = angle W</h3>
Explanation:
We are given the sides are congruent due to the tickmarks. Specifically
TU = WV (single tickmarks)
TV = WX (double tickmarks)
So we just need the "A" of "SAS". The A is between the two S letters, so the angle is between the two sides. For triangle TUV, the angle T is between the two sides with the tickmarks. Similarly, angle W is between the tickmarked sides of triangle WVX.
If we know that angle T = angle W, then we have enough information to use SAS.
<span>The maxima of a differential equation can be obtained by
getting the 1st derivate dx/dy and equating it to 0.</span>
<span>Given the equation h = - 2 t^2 + 12 t , taking the 1st derivative
result in:</span>
dh = - 4 t dt + 12 dt
<span>dh / dt = 0 = - 4 t + 12 calculating
for t:</span>
t = -12 / - 4
t = 3
s
Therefore the maximum height obtained is calculated by
plugging in the value of t in the given equation.
h = -2 (3)^2 + 12 (3)
h =
18 m
This problem can also be solved graphically by plotting t
(x-axis) against h (y-axis). Then assigning values to t and calculate for h and
plot it in the graph to see the point in which the peak is obtained. Therefore
the answer to this is:
<span>The ball reaches a maximum height of 18
meters. The maximum of h(t) can be found both graphically or algebraically, and
lies at (3,18). The x-coordinate, 3, is the time in seconds it takes the ball
to reach maximum height, and the y-coordinate, 18, is the max height in meters.</span>
x+3
