Answer:
The correct answer is option d.
Explanation:
The production of Acetyl-CoA takes place by the dissociation of both carbohydrates and lipids in the process of glycolysis and beta-oxidation. It then moves into the TCA cycle in the mitochondria and combines with oxaloacetate to give rise to citrate.
In the given case, no labeling will be found in the acetyl-CoA. The labeled C3 and C4 carbon of glucose signify the carboxyl carbon of pyruvate. In the succeeding reactions of the transformation of pyruvate to acetyl-CoA, the carboxyl carbon gets lost in the form of carbon dioxide. Thus, acetyl-CoA does not comprise any labeled C3 and C4 of glucose.
In photosynthesis, using light energy, plants convert CO2 and H2O into O2 and C6H12O6
CO2= carbon dioxide
H2O= water
O2= oxygen
C6H12O6= glucose
Answer:
Reactants: hydrogen and oxygen
Products: water
Explanation:
The reactants are what goes into a reaction, i.e. what is reacting. The products are what is formed. The reactants are usually shown on the left, and the products are usually shown on the right.
We can see in this equation that hydrogen (2H2) is reacting with oxygen (O2) to form water (2H2O). Therefore the reactants are hydrogen and oxygen, and the product is water.
I think Your answer is false.
Regulation of HMG-CoA reductase is termed as the rate of controlling enzyme of the mevalonate pathway which produces other isoprenoid and cholesterol.
The regulation of cholesterol is done by regulating the rate which determines step catalyzed by HGM -CoA reductase.
There is long-term and short-term regulation where HGM-CoA is inhibited by phosphorylation and catalyzed of proteins. There is regulated proteolysis of HGM-CoA reductase where degradation of HMG-CoA reductase by oxidized derivatives of cholesterol.
