The first polynomial is $y -4yz^2-3$ and let the second polynomial be P(y,z).

If the sum of two polynomials is $-yz^2-3z^2-4y+4$ , then $y-4yz^2-3+P(y,z)=-yz^2-3z^2-4y+4$ .

Take the first polynomial from the left side to the right side:

$P(y,z)=-yz^2-3z^2-4y+4 -(y-4yz^2-3),\\ P(y,z)=-yz^2-3z^2-4y+4 -y+4yz^2+3,\\ P(y,z)=3yz^2-3z^2-5y+7$ .

Answer: the second polynomial is $3yz^2-3z^2-5y+7$ .

3 0

4 years ago

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The roots of the equation x2 - 14x + 48 = 0) are

MrRissso [65]

Answer:

${x}^{2} - 14x + 48 = 0 \\ {x}^{2} - 6x -8 x + 48 = 0 \\ x(x - 6) - 8(x - 6) = 0 \\ (x - 6)(x - 8) = 0 \\ \boxed{ x = 6\: and \: 8}$

4) <em><u>6 and 8</u></em> is the right answer.

5 0

2 years ago

Someone help me with these please!!!! <33

Triss [41]

Answer:

120 = m h = 2

Step-by-step explanation:

5 0

3 years ago

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Calculate the shaded areas for c and d

KiRa [710]

C)
Area of full triangle
1/2(8)(6)=24cm^2
Area of non shaded triangle
1/2(4)(3)=6cm^2
Area of full minus area of small triangle
24-6=18cm^2

D)
Area of Big rectangle
(4)(12)=48
Area of non shaded triangle
1/2(9)(4)=18
Area of Big rectangle minus non shaded triangle
48-18=30cm^2

5 0

3 years ago