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Licemer1 [7]
3 years ago
9

Help me out please .

Mathematics
2 answers:
Marta_Voda [28]3 years ago
6 0
I’m pretty sure it’s A but it could also me C
Hopes it right.
irina1246 [14]3 years ago
3 0

Answer:

I think the answer is D or 36

Step-by-step explanation:

You might be interested in
A square has a side of 3x - 4 what is the area of the Square in terms of x?
Doss [256]

Answer:

9x2−24x+16

Hope this helps!

Step-by-step explanation:

The formula for a square is side times side since every side is of equal length. Because we are leaving the answer in terms of x you just multiply 3x-4 by 3x-4 and simplify and you get 9x2−24x+16

Please mark as brainliest :)

3 0
3 years ago
Can someone help me with this one
Nostrana [21]
It’s name would be a monomial because it only has 1 term. (Terms are departed by addition or subtraction sign) The degree would be the highest exponent in the polynomial, in this case we only have 1 term so the degree of that term is 2
6 0
2 years ago
Aubrey worked at the concession stand during a recent sporting event at her high school. During the first hour of the event, she
ella [17]

Answer:

cost of nachos = $3.45

Cost of tacos = $1.5

Step-by-step explanation:

Let

x = cost of nachos

y = cost of tacos

11x + 18y = 64.95 (1)

6x + 15y = 43.20 (2)

Multiply (1) by 6 and (2) by 11 to eliminate x

66x + 108y = 389.70

66x + 165y = 475.20

Subtract to eliminate x

165y - 108y = 475.20 - 389.70

57y = 85.50

y = 85.50/57

y = 1.5

Substitute y = 1.5 to find x

11x + 18y = 64.95 (1)

11x + 18(1.5) = 64.95

11x + 27 = 64.95

11x = 64.95 - 27

11x = 37.95

x = 37.95/11

x = 3.45

cost of nachos = $3.45

Cost of tacos = $1.5

8 0
3 years ago
A contractor wishes to build 9 houses, each different in design. In how many ways can he place these houses on a street if 6 lot
Lana71 [14]
Hello,

Let's put the 6 houses on side: 6P9=9*8*7*6*5*4/6! = 84

For each choice there are 3! choices pour the other side

84*3!=504

7 0
3 years ago
Read 2 more answers
HELP!!!
ella [17]

Answer:

120

Step-by-step explanation:

We are given that the function for the number of students enrolled in a new course is f(x) = 4^{x}-1.

It is asked to find the average increase in the number of students enrolled per hour between 2 to 4 hours.

We know that the average rate of change is given by,

A = \frac{f(x)-f(a)}{x-a},

where f(x)-f(a) is the change in the function as the input value (x-a) changes.

Now, the number of students enrolled at 4 = f(4) = f(x) = 4^{4}-1 = 255 and the number of students enrolled at 2 = f(2) = f(x) = 4^{2}-1 = 15

So, the average increase A=\frac{f(4)-f(2)}{4-2} = A=\frac{255-15}{4-2} = A=\frac{240}{2} = 120.

Hence, the average increase in the number of students enrolled is 120.

3 0
3 years ago
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