4x-8=9x+2
4x=9x+10
-5x=10
5x=-10
x=-2
D= 140° because you take 180 minus the opposite angle
Since length of diagonal ( 
) is less than diameter of circle ( 11 cm ) , Therefore , the square will fit inside the circle without touching the edge of the circle.
<u>Step-by-step explanation:</u>
Here we have , A circle has diameter of 11 cm A square has side length of 7 cm . Use Pythagoras’ Theorem to show that the square will fit inside the circle without touching the edge of the circle . Let's find out:
We know the concept that for any square to fit inside the circle without touching the edge of circle , diagonal of square must be less than diameter of circle . Let's find out length of diagonal by using Pythagoras Theorem :
For a square , 
⇒ 
⇒ 
⇒ 
⇒
Since length of diagonal ( ) is less than diameter of circle ( 11 cm ) , Therefore , the square will fit inside the circle without ruching the edge of the circle.
Answer:
The area of circle A is 16 times the area of circle B.
Step-by-step explanation:
he area of circle A is three times the area of circle B.
It depends on the value of π.
It depends on the actual diameters of the circles.
The area of circle A is 16 times the area of circle
the circumference of a circle = 2 x pi x r
Let imagine that the radius of B is 2cm
then the circumference of B = 2 x 2 x pi = 4pi
If the circumference of a is 4 times that of B, it means the circumference is 16 and the radius is 8
Area of a circle is pi x r^2
Area of B = pi x 2^2 = 4pi
Area of A = pi x 8^2 = 64pi
64/4 = 16 pi
