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nasty-shy [4]
3 years ago
6

A(n) = -5 + 6(n - 1)

Mathematics
2 answers:
Fudgin [204]3 years ago
5 0
An/n= -5/n + 6(n-1)/n ; n is not equal to 0
Andreas93 [3]3 years ago
3 0

Answer:

domain is all reall numbers

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EastWind [94]

Answer:

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Sophia has $8 dollars to spend on lunch
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What is the question that goes to this statement?
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The length of a rectangle is (2x –1) units, and the width is (x − 2) units. The area of the rectangle is 20 square units. What i
DedPeter [7]

Length of the given rectangle is 8 units.

Option - D

<u>Solution:</u>

Given that  

Length of a rectangle = (2x-1)\text { units}

Width of a rectangle = (x-2)\text{ units}

Area of rectangle = 20 square units  

Need to calculate length of rectangle.

\text { Formula of area of rectangle }=\text { Length of a rectangle } \times \text { Width of a rectangle }

Substituting given value of Area of rectangle and expressions for length and width of rectangle in formula, we get

20=(x-2)(2 x-1)

On solving above equation for x we get

\begin{array}{l}{20=x(2 x-1)-2(2 x-1)} \\\\ {\Rightarrow 20=2 x^{2}-x-4 x+2} \\\\ {\Rightarrow 2 x^{2}-5 x+2-20=0} \\\\ {\Rightarrow 2 x^{2}-5 x-18=0}\end{array}

On splitting the middle term in such a way that product of split terms comes as 2x^2\times -18 = -36x^2 and summation comes as -5x, we get

\begin{array}{l}{\Rightarrow 2 x^{2}+4 x-9 x-18=0} \\\\ {=>2 x(x+2)-9(x+2)=0} \\\\ {\Rightarrow(2 x-9)(x+2)=0} \\\\ {\Rightarrow(2 x-9)=0 \text { or }(x+2)=0} \\\\ {\Rightarrow x=\frac{9}{2} \text { or } x=-2}\end{array}

\begin{array}{l}{\text { When } x=\frac{9}{2}, \text { length }=(2 x-1) \text { units }=\left(2 \times \frac{9}{2}-1\right)=8 \text { units }} \\\\ {\text { When } x=-2, \text { length }=(2 x-1) \text { units }=(2 \times(-2)-1)=-5 \text { units }}\end{array}

As length cannot be negative hence we can ignore negative value.

So length is 8 units.

3 0
3 years ago
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