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Advocard [28]
3 years ago
10

(8^5)^0 + (7 + 3)^6 x 10^-8 Please answer!!!

Mathematics
1 answer:
sergeinik [125]3 years ago
7 0

Answer:

1.01 m8

Step-by-step explanation:

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I put an answer but I’m unsure of it, any help would be much appreciated!!
Darya [45]
First you need to change 45 feet to 540 inches.

Now you can compare the two ratios:
1 : 25 and 25 : 540

We now need to change the second ratio to a unit rate:
25:540 as a unit rate would be 1 : 21.6 and this is steeper than the a 1 : 25 drop

So, your answer would be: pipe drops to much vertically to function properly
8 0
3 years ago
What is a equivalent expression for 3y+y+4+y
fenix001 [56]

Answer:

5y+4

we can write it like:

3y+y+y+4

And sum of 3y+y+y is 5y

So answer is 5y+4

7 0
4 years ago
I have a test guys (One Smart Man Op Plays)
lara31 [8.8K]

Answer:

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Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
A bird drops a stick from the top of Miami Tower. The height of the stick after x seconds is given by f(x) = 625 - 16x^2.
Leni [432]

ANSWER

The maximum value is 625

EXPLANATION

The height of the stick that the bird dropped is modeled by the function;

f(x) = 625 - 16x^2

This function is already in the vertex form.

Let me rewrite it clearly for you to see.

f(x) = - 16(x - 0)^2 + 625

When we compare this to;

f(x)=a(x-h)^2+k

we have h=0 and k=625.

k=625 is the y-value of the vertex.

This is the maximum value on the graph of this function.

3 0
3 years ago
If n is a positive integer, how many 5-tuples of integers from 1 through n can be formed in which the elements of the 5-tuple ar
sleet_krkn [62]

This question is incomplete, the complete question is;

If n is a positive integer, how many 5-tuples of integers from 1 through n can be formed in which the elements of the 5-tuple are written in increasing order but are not necessarily distinct.

In other words, how many 5-tuples of integers  ( h, i , j , m ), are there with  n ≥ h ≥ i ≥ j ≥ k ≥ m ≥ 1 ?

Answer:

the number of 5-tuples of integers from 1 through n that can be formed is [ n( n+1 ) ( n+2 ) ( n+3 ) ( n+4 ) ] / 120

Step-by-step explanation:

Given the data in the question;

Any quintuple ( h, i , j , m ), with n ≥ h ≥ i ≥ j ≥ k ≥ m ≥ 1

this can be represented as a string of ( n-1 ) vertical bars and 5 crosses.

So the positions of the crosses will indicate which 5 integers from 1 to n are indicated in the n-tuple'

Hence, the number of such quintuple is the same as the number of strings of ( n-1 ) vertical bars and 5 crosses such as;

\left[\begin{array}{ccccc}5&+&n&-&1\\&&5\\\end{array}\right] = \left[\begin{array}{ccc}n&+&4\\&5&\\\end{array}\right]

= [( n + 4 )! ] / [ 5!( n + 4 - 5 )! ]

= [( n + 4 )!] / [ 5!( n-1 )! ]

= [ n( n+1 ) ( n+2 ) ( n+3 ) ( n+4 ) ] / 120

Therefore, the number of 5-tuples of integers from 1 through n that can be formed is [ n( n+1 ) ( n+2 ) ( n+3 ) ( n+4 ) ] / 120

4 0
3 years ago
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