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A seek tasks10+0.1xTms where T is the number of tracks of motion from one request to the next and 10.is a movement time constant.(b) one full rotation takes 7ms .(c) Transfer time is 1.2 Ms per sectors
Answer:
0J
Explanation:
Mass of the lump M1 = 1.0 kg, initial velocity of the lump U1 = 2m/s to the right,
mass of the metal sphere M2 = 0.5kg, initial velocity of the metal sphere M2 = -4m/s to the left. using conservation law of momentum;
M1U1 + M2U2 = V (M1 + M2)
(1.0 × 2) + (0.5 × -4) = V (1 + 0.5)
2 -2 = V (1.5)
0 = V (1.5)
divide both side by 1.5
0/1.5 = V 1.5/1.5
V = 0
since final velocity after sticking together of the two masses equals zero then their combined kinetic energy will also equal to zero
1/2 V(M1 +M2)
1/2 ×0 × 1.5 = 0J
Answer:
x = 9/25, y = 7/25, z = 4/25
Explanation:
step 1: solve for y in first equation to use substitution
y = -2x + 1
step 2: insert into second equation to eliminate y variable and work with two variables
3(-2x+1) + z = 1 (now distribute)
-6x + 3 + z = 1 (bring over the -3)
-6x + z = -2
step 3: now left with -6x + z = -2 and x + 4z = 1, so eliminate z
-6x + z = -2 (multiply by 4)
4(-6x + z = -2)
-24x + 4z = -8
-
x + 4z = 1 (brought down third equation)
-25x = -9
x = 9/25
then just plug in x into the third equation to solve for z, followed by plugging it into the first equation to solve for y. you should end with y = 7/25 and z = 4/25
A. five
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