All categories

3 years ago

Solve for x. Round your answer to two decimal places. Show your work for full credit.

Mathematics

1 answer:

omeli [17]3 years ago

5 0

Answer:

x ≈ 14.30

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS
Equality Properties

Trigonometry

sin∅ = opposite over hypotenuse

Step-by-step explanation:

Step 1: Define variables

∅ = 39°

opposite leg = 9

hypotenuse = x

Step 2: Solve for x

Substitute: sin39° = 9/x
Multiply x on both sides: xsin39° = 9
Isolate x: x = 9/sin39°
Evaluate: x = 14.3011
Round: x ≈ 14.30

You might be interested in

Help me i need help ok try to explain and ok ok ok ok ok ok ok ok

Kaylis [27]

Question 9

18, 28, 6, 54

Question 10

Correct Number: 5

Incorrect Number: 6

7 0

3 years ago

10x-2x in fewer terms

Aleks04 [339]

Answer:

Step-by-step explanations:

10x - 2x

5 0

3 years ago

A group of health care workers were asked how many times per week they visited a gym. The data is shown on the dot plot. Select

Yakvenalex [24]

the correct answer is B &/or D, hope this helped (:

7 0

3 years ago

Read 2 more answers

What is the value of x? Enter your answer in the box.

charle [14.2K]

Hi there!

We know that RST is an equilateral(all 3 sides the same length) triangle, and is therefore equiangular(all 3 angles the same value). Therefore, angle S and is equal to one-third of the triangle's angle measure.

180/3=60

60=7x+4

56=7x

x=8

-AwesomeRepublic :)

4 0

4 years ago

Read 2 more answers

true or false If x represents a random variable with mean 114 and standard deviation 40, then the standard deviation of the samp

Goshia [24]

Answer:

$\mu = 114, \sigma = 40$

We also know that we select a sample size of n =100 and on this case since the sample size is higher than 30 we can apply the central limit theorem and the distribution for the sample mean would be given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And the standard deviation for the sampling distribution would be:

$\sigma_{\bar X}= \frac{40}{\sqrt{100}}= 4$

So then the answer is TRUE

Step-by-step explanation:

Let X the random variable of interest and we know that the true mean and deviation for this case are given by:

$\mu = 114, \sigma = 40$

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And the standard deviation for the sampling distribution would be:

$\sigma_{\bar X}= \frac{40}{\sqrt{100}}= 4$

So then the answer is TRUE

6 0

3 years ago