Answer: The sum of their ages is 42
Step-by-step explanation:
This can be translated to:
in 15 years from now, Jorge's age will be 2 times the age of Eduardo.
If 6 years ago the age of Jorge was the triple of the one of Eduardo.
Find the sum of their ages:
If E is Eduardo's age and J is Jorge's age, we have a system of equations:
J + 15 = 2(E + 15)
J - 6 = 3*E
The first step is isolating one of the variables in one of the equations, let's isolate J in the second equation:
J - 6 = 3E
J = 3E +6
Now we can replace it in the first equation:
J + 15 = 2E
3E + 6 + 15 = 2E + 30
3E + 21 = 2E + 30
3E - 2E = 30 - 21 = 9
E = 9
Eduardo is 9 years old:
J = 3E + 6 = 3*9 + 6 = 27 + 6 = 33
Jorge is 33 years old.
then E + J = 33 + 9 = 42
Answer:
6
Step-by-step explanation:
1-(-1) ends you with 5
1 -(-1) ends you with 4
1- (-1) end you with 3
1 - (-1) ends you with 2
1 - (-1) end you with 1
1 - (-1) ends you with 0
Answer:
3/1 or 3
Step-by-step explanation:
45/15 divided by 15 = 3/1
Answer:
I do not believe you can solve this unless the variable mean something and it is specified
3/4 will become 1/2 and 6/7 will become 1/2 too
