Answer:
The area of triangles are 16 cm^2 and 49 cm^2
Step-by-step explanation:
we know that
If two figures are similar, the ratio of its perimeters is equal to the scale factor and the ratio of its areas is equal to the scale factor squared
Let
z ----> the scale factor
x ----> the area of the smaller triangle in square centimeters
y ----> the area of the larger triangle in square centimeters
we know that
so
-----> equation A
----> equation B
solve the system by substitution
substitute equation A in equation B
solve for y
Find the value of x
therefore
The area of triangles are 16 cm^2 and 49 cm^2
Well first you need to convert the mixed numbers into improper fractions like so
3 1/5 would be 16/5 because 3 times 5= 15+1=16
the same with 1 4/5 but you can do this one a bit differently like so- 1=5/5 + 4/5 = 9/5
So now we move on to the subtraction part of the problem. 16/5-9/5= 7/5 because we know 16-9=7
But now you got to convert this improper fraction back into a proper fraction: 7/ 1 2/5 because 5 goes into 7 one time with a remainder of 2 (2/5)
So the answer would be: Ethan read 1 2/5 more books than he did this week.
3pi/2. The unit circle is 2pi
I think the answer is C-No solutions
Answer:
2357.14
Step-by-step explanation:
x - .30x = 1500(1.10)
.7x = 1650
x = 2357.14
