Answer:
<h3>
f(x) = - ⁴/₉(x - 3)² + 6</h3>
Step-by-step explanation:
The vertex form of the equation of the parabola with vertex (h, k) is:
f(x) = a(x - h)² + k
So for vertex (3, 6) it will be:
f(x) = a(x - 3)² + 6
<u>y intercept: 2</u> means f(0) = 2
f(0) = a(0 - 3)² + 6
2 = a(-3)² + 6
2 -6 = 9a + 6 -6
-4 = 9a
a = ⁻⁴/₉
Therefore:
The vertex form of quardatic function with vertex: (3,6) and y intercept: 2 is
<u>f(x) = - ⁴/₉(x - 3)² + 6</u>
Answer:
one solution
Step-by-step explanation:
2/3(3y+6)=0
Multiply by 3/2
3/2 *2/3(3y+6)=0*3/2
3y+6 = 0
Subtract 6 from each side
3y = -6
Divide by 3
3y/3 = -6/3
y = -2
There is one solution
Answer:
A) 4
Step-by-step explanation:
There are a couple of ways to get this but this is how I did it:
1. Multiply the second equation by 1/4 to get the same fraction for y as the one in the first equation
1/4 x + 1/8 y = 2
1/4 (1/3 x + 1/2 y = 4)
1/12 x + 1/8 y = 1
2. Subtract the first equation from the new equation
1/12 x + 1/8 y = 1
<u> - 1/4 x - 1/8 y = -2</u>
-1/6 x= -1
3. Divide both sides by -1/6
<u>-1/6</u> x= <u>-1</u>
-1/6 -1/6
x = 6
4. Substitute 4 in for x in the original equation:
1/4 (6) + 1/8y = 2
6/4 + 1/8y = 2
1/8y = 1/2
y = 4
U have to times by 2 it will it will change
