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steposvetlana [31]
3 years ago
6

Help please this is due soon!!!!!!!

Mathematics
2 answers:
NNADVOKAT [17]3 years ago
4 0

Answer:

a)22/3

b)d. 2/11

Step-by-step explanation:

you are correct

tensa zangetsu [6.8K]3 years ago
3 0

Answer:

Step-by-step explanation:

Slope of (-4,7),(-7,-15) is 22/3

Slope of the function is 2/11

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Which of the following represents the zeros of f(x) = 2x3 − 5x2 − 28x + 15?
likoan [24]

\mathrm{Use\:the\:rational\:root\:theorem}

a_0=15,\:\quad a_n=2

\mathrm{The\:dividers\:of\:}a_0:\quad 1,\:3,\:5,\:15,\:\quad \mathrm{The\:dividers\:of\:}a_n:\quad 1,\:2

\mathrm{Therefore,\:check\:the\:following\:rational\:numbers:\quad }\pm \frac{1,\:3,\:5,\:15}{1,\:2}

-\frac{3}{1}\mathrm{\:is\:a\:root\:of\:the\:expression,\:so\:factor\:out\:}x+3

-\frac{3}{1}\mathrm{\:is\:a\:root\:of\:the\:expression,\:so\:factor\:out\:}x+3

\mathrm{Compute\:}\frac{2x^3-5x^2-28x+15}{x+3}\mathrm{\:to\:get\:the\:rest\:of\:the\:eqution:\quad }2x^2-11x+5

=\left(x+3\right)\left(2x^2-11x+5\right)

Factor: 2x^2-11x+5

2x^2-11x+5=\left(2x^2-x\right)+\left(-10x+5\right)

=x\left(2x-1\right)-5\left(2x-1\right)

2x^3-5x^2-28x+15=\left(x+3\right)\left(x-5\right)\left(2x-1\right)

\left(x+3\right)\left(x-5\right)\left(2x-1\right)=0

\mathrm{Using\:the\:Zero\:Factor\:Principle:}

thus zeros of f(x) is

x=-3,\:x=5,\:x=\frac{1}{2}

5 0
3 years ago
Read 2 more answers
Karen raked 3/5 of the yard he yard. Minute raked 1/3 of the amount Karen raked. How much of the yard did Minnie rake
disa [49]
(3/5)(1/3)=1/5 of the yard
3 0
3 years ago
Need help before 5:30pm i also have to show my work.
SpyIntel [72]

I can help!! But could you tell me what the equations are?

6 0
3 years ago
Help me out here please.
Vilka [71]

Answer:

just remove the parentheses and add the numbers

Step-by-step explanation:

5 0
3 years ago
An elementary school class ran 1 mile in an average of 11 minutes with a standard deviation of 3 minutes. Rachel, a student in t
EleoNora [17]

Answer:

Rachel

Step-by-step explanation:

We need to measure how far (towards the left) are the students from the mean in<em> “standard deviations units”</em>.  

That is to say, if t is the time the student ran the mile and s is the standard deviation of the class, we must find an x such that

mean - x*s = t

For Rachel we have

11 - x*3 = 8, so x = 1.  

Rachel is <em>1 standard deviation far (to the left) from the mean</em> of her class

For Kenji we have

9 - x*2 = 8.5, so x = 0.25

Kenji is <em>0.25 standard deviations far (to the left) from the mean</em> of his class

For Nedda we have

7 - x*4 = 8, so x = 0.25

Nedda is also 0.25 standard deviations far (to the left) from the mean of his class.

As Rachel is the farthest from the mean of her class in term of standard deviations, Rachel is the fastest runner with respect to her class.

8 0
3 years ago
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