Question

IF CORRECT, I WILL MARK AS BRAINLIEST

Answer 1

a)

$P(t) = 19100. e^{0.06t}$

b) P(8) =30866

Use formula:

$P(t) = P. e^{rt}$

a)

Here, P = 19100

r = 6% = 0.06

$P(t) = 19100. e^{0.06t}$

b) t = 2008 - 2000 = 8

$P(8) = 19100. e^{0.06\times 8}$

$P(8) = 19100. e^{0.48}$

$P(8) = 19100\times 1.616\\\\P(8) = 30,865.6\\\\P(8) \approx 30,866$