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3 years ago

Hunter jogs 6 miles in 30 minutes. What is his rate? What is his rate?

Mathematics

1 answer:

Ann [662]3 years ago

8 0

To get your answer you will divide 30/6. Therefore you get 5. His rate is 5. Hope this helps! Tell me if I am wrong.

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Given: ZDEF is a right angle. Using a paragraph proof, prove 41 is acute.

Slav-nsk [51]

Let G be some point on the diagonal line away from point E.

Angle DEG represents angle 1.

We're given that angle DEF is a right angle which means it's 90 degrees. Angle DEG is some angle smaller than 90 degrees. By definition, that must mean angle 1 is acute. Any acute angle is smaller than 90 degrees. There's not much else to say other than this is just a definition problem.

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Extra side notes:

If angle 1 was a right angle, then that would mean angle GEF would have to be 0 degrees; however the diagram shows this isn't the case.

If angle 1 was obtuse, then there's no way we'd be able to fit it into angle DEF. In other words, there's no way to have an angle larger than 90 fit in a 90 degree angle.

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3 years ago

Robert drew a parallelogram with 2 55 degree angles. What are the measures of the 2 other angles? Both of the angles have to be

Licemer1 [7]

Angles in a parallelogram have to equal 360.

Let x represent the measurement of the unknown angle.

2(55) + 2x = 360
110 + 2x = 360
2x = 250
x = 125

125 degrees

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3 years ago

Picture available : what percent <br> PLEASE HELP: 10 points

jekas [21]

D is the answer for the question

7 0

3 years ago

Read 2 more answers

A street light is at the top of a 25 ft pole. A 4 ft tall girl walks along a straight path away from the pole with a speed of 6

Burka [1]

Answer:

Tip of the shadow of the girl is moving with a rate of 7.14 feet per sec.

Step-by-step explanation:

Given : In the figure attached, Length of girl EC = 4 ft

Length of street light AB = 25 ft

Girl is moving away from the light with a speed = 6 ft per sec.

To Find : Rate ( $\frac{dw}{dt}$ ) of the tip (D) of the girl's shadow (BD) moving away from th

light.

Solution : Let the distance of the girl from the street light is = x feet

Length of the shadow CD is = y feet

Therefore, $\frac{dx}{dt}=6$ feet per sec. [Given]

In the figure attached, ΔAFE and ΔADE are similar.

By the property of similar triangles,

$\frac{x}{21}=\frac{x+y}{25}$

25x = 21(x + y)

25x = 21x + 21y

25x - 21x = 21y

4x = 21y

y = $\frac{4x}{21}$

Now we take the derivative on both the sides,

$\frac{dy}{dt}=\frac{4}{21}\times \frac{dx}{dt}$

= $\frac{4}{21}\times 6$

= $\frac{8}{7}$

≈ 1.14 ft per sec.

Since w = x + y

Therefore, $\frac{dw}{dt}= \frac{dx}{dt}+\frac{dy}{dt}$

$\frac{dw}{dt}=6+1.14$

= 7.14 ft per sec.

Therefore, tip of the shadow of the girl is moving with a rate of 7.14 feet per sec.

3 0

4 years ago

Find an equation for the line with the given properties. Express your answer using the general form or the slope-intercept form

Damm [24]

Answer:

$y=-3x+4$

Step-by-step explanation:

To get the equation in the slope-intercept form first, put the equation in slope-point form using the information given. The slope-point form is $y-(-2)=-3(x-2)$ . Then solve for y.

Distribute -3 to $(x-2)$ ,

$y-(-2)=-3x+6$

Then, add -2 to both sides,

$y=-3x+4$

This is your final answer; the slope is -3 and the y-intercept is 4. There are also a few other ways to solve but I find this the easiest.

3 0

3 years ago